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3 years ago

The three incoming currents at a

Mathematics

1 answer:

Dmitry [639]3 years ago

6 0

Answer:

Measure of the third outgoing current will be 0.34 ampere.

Step-by-step explanation:

Kirchhoff's Current Law states that total current entering a circuit's junction is exactly equal to the total current leaving the same junction.

By this rule,

Sum of input three currents = Sum of three outgoing currents

0.38 + 0.75 + 0.29 = 0.48 + 0.6 + i

1.42 = 1.08 + i

i = 0.34

Therefore, measure of the third outgoing current will be 0.34 ampere.

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Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

$SS = \sum_{i=1}^n (X_i -\bar X)^2$

And the sample variance for this case can be calculated from this formula:

$s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

Part c

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$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

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