Answer:
Measure of the third outgoing current will be 0.34 ampere.
Step-by-step explanation:
Kirchhoff's Current Law states that total current entering a circuit's junction is exactly equal to the total current leaving the same junction.
By this rule,
Sum of input three currents = Sum of three outgoing currents
0.38 + 0.75 + 0.29 = 0.48 + 0.6 + i
1.42 = 1.08 + i
i = 0.34
Therefore, measure of the third outgoing current will be 0.34 ampere.
