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ANTONII [103]
3 years ago
14

The three incoming currents at a

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

Answer:

Measure of the third outgoing current will be 0.34 ampere.

Step-by-step explanation:

Kirchhoff's Current Law states that total current entering a circuit's junction is exactly equal to the total current leaving the same junction.

By this rule,

Sum of input three currents = Sum of three outgoing currents

0.38 + 0.75 + 0.29 = 0.48 + 0.6 + i

1.42 = 1.08 + i

i = 0.34

Therefore, measure of the third outgoing current will be 0.34 ampere.

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write the equation of the line that is parallel to y = 4x -7 and passes through the point (-2, -5). show your work.​
natita [175]

Answer:

y = 4x + 3

Step-by-step explanation:

To do this, put the new line into the form y = mx + b where m is the slope and b is the y-intercept.

When two lines are parallel, they have the same slope. Since, the slope of the first line is 4, that means the slope of the second line is also 4.

So far, the equation is y = 4x + b.

Then, since you know (-2, -5) is a solution, x = -2, y = -5 is a solution so you can plug this into the equation.

This would be:

-5 = 4 * -2 + b

-5 = -8 + b

3 = b

This means the equation is y = 4x + 3.

7 0
3 years ago
0.64 x 0.81 help im on a time limit ಥ_ಥ
lorasvet [3.4K]

Answer:

0.5184

Step-by-step explanation:

hope this helps!!!

8 0
3 years ago
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Can a triangle have sides with the given lengths? Explain.
Amiraneli [1.4K]

Answer:

Option A.

Step-by-step explanation:

12 cm, 17cm, 25 cm

7 0
2 years ago
PLEASE HELP ME OUT..........
Vlad1618 [11]
Here is your answer

\bold{x=12}

REASON:

Concept used: The opposite sides of a parallelogram are equal.

So, in above given figure

3x+7=5x-17 (measures of opposite sides)

5x-3x= 17+7

2x= 24

x= 24/2

x= 12

HOPE IT IS USEFUL
6 0
3 years ago
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What is the simplified form of 2/x^2-x - 1/x?
Pachacha [2.7K]

Answer:  \bold{(C)\ \dfrac{3 - x}{x(x-1)}}

<u>Step-by-step explanation:</u>

   \dfrac{2}{x^2-x}-\dfrac{1}{x}

=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}

=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}\bigg(\dfrac{x-1}{x-1}\bigg)

=\dfrac{2}{x(x-1)}+\dfrac{-x+1}{x(x-1)}

=\dfrac{2-x+1}{x(x-1)}

=\dfrac{3-x}{x(x-1)}

8 0
3 years ago
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