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3 years ago

The three incoming currents at a

Mathematics

1 answer:

Dmitry [639]3 years ago

6 0

Answer:

Measure of the third outgoing current will be 0.34 ampere.

Step-by-step explanation:

Kirchhoff's Current Law states that total current entering a circuit's junction is exactly equal to the total current leaving the same junction.

By this rule,

Sum of input three currents = Sum of three outgoing currents

0.38 + 0.75 + 0.29 = 0.48 + 0.6 + i

1.42 = 1.08 + i

i = 0.34

Therefore, measure of the third outgoing current will be 0.34 ampere.

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3 3/5+ 4 1/8=<br> PLS PLS PLS PLS ANSWER

Jet001 [13]

I think the answer is 7.725 so sorry if I’m wrong but see if that answer is correct

5 0

3 years ago

A sandwich shop is ordering apples and grapes to make chicken salad.Apples cost $2.19 per pound and grapes cost $2.60 per pound.

andrew11 [14]

Answer:

Grapes=19.51

Step-by-step explanation:

Apples=$2.19 per pound

Grapes=$2.60 per pound

Apples+Grapes=20 pounds

A+G=20

A=20-G

Equation is

PaA+PgG=35.80

2.19A+2.60G=35.80

2.19(20-G)+2.60G=35.80

43.8-2.19G+2.60G=35.80

43.8-0.41G=35.80

-0.41G=35.80-43.8

-0.41G=-8

Divide both sides by 0.41

G=19.51 pounds

Recall

A=20-G

A=20-19.51

A=0.49 pounds

8 0

3 years ago

The length of a rectangle is 4 units shorter than half the width. If the length of the rectangle is 18 units, which equation can

never [62]

Answer:

The width is 11 units.

Step-by-step explanation:

First, you have to add 4 to 18 which is 22. Then divide by 2.

8 0

3 years ago

19) Two of the dozen eggs in a carton are cracked. About what percent of the carton is not cracked? (Round to the nearest whole

777dan777 [17]

Answer:

$83%$ %

Step-by-step explanation:

We have that $2/12=1/6$ of the eggs are cracked, so $1-1/6=5/6$ of the eggs are not cracked.

Recall that $1/6=0.1666666666...$ . This means that $5/6=1-1/6=1-0.166666666...=0.833333333...$ .

Rounding this to the nearest whole percent gives $83%$ %.

7 0

3 years ago

Suppose that a brand of lightbulb lasts on average 1730 hours with a standard deviation of 257 hours. Assume the life of the lig

Debora [2.8K]

Answer:

P [ 1689 ≤ X ≤ 2267 ] = 54,88 %

Step-by-step explanation:

Normal Distribution

Mean μ₀ = 1730

Standard Deviation σ = 257

We need to calculate z scores for the values 1689 and 2267

We apply formula for z scores

z = ( X - μ₀ ) /σ

X = 1689 then

z = (1689 - 1730)/ 257 ⇒ z = - 41 / 257

z = - 0.1595

And from z table we get for z = - 0,1595

We have to interpolate

- 0,15 0,4364

- 0,16 0,4325

Δ = 0.01 0.0039

0,1595 - 0,15 = 0.0095

By rule of three

0,01 0,0039

0,0095 x ?? x = 0.0037

And 0,4364 - 0.0037 = 0,4327

Then P [ X ≤ 1689 ] = 0.4327 or P [ X ≤ 1689 ] = 43,27 %

And for the upper limit 2267 z score will be

z = ( X - 1730 ) / 257 ⇒ z = 537 / 257

z = 2.0894

Now from z table we find for score 2.0894

We interpolate and assume 0.9815

P [ X ≤ 2267 ] = 0,9815

Ths vale already contains th value of P [ X ≤ 1689 ] = 0.4327

Then we subtract to get 0,9815 - 0,4327 = 0,5488

Finally

P [ 1689 ≤ X ≤ 2267 ] = 0,5488 or P [ 1689 ≤ X ≤ 2267 ] = 54,88 %

8 0

3 years ago