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GuDViN [60]
3 years ago
6

Find the real solution for:

Mathematics
1 answer:
Advocard [28]3 years ago
6 0

Answer:

none of the above

Step-by-step explanation:

p^3 = 125

Rewrite 125 as 5^3

p^3 = 5^3

Take the cube root of each side

(p^3) ^ (1/3) = ( 5^3) ^ (1/3)

p = 3

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Adar, Chi, and Melissa each left the party by themselves. In how many different orders can they leave?
borishaifa [10]

Answer:

6

Step-by-step explanation:

3*2*1

6 0
3 years ago
An engineer was supposed to draw a line exactly 7/10 centimeters long. An error was made, and he drew the line 9/10 centimeters
Paha777 [63]

Answer:

2/10 or 1/5 if you want it simplified

Step-by-step explanation:

9/10 is basically 9 and 7/10 is 7 so 9 - 7 is 2 and we need to add the /10 back so it's 2/10 or 1/5

7 0
2 years ago
Read 2 more answers
Express 0.00048 in scientific notation. hintx
Olenka [21]
(number less tan 10 and more than or equal to 1) times (10^m)

0.00048=4.8 times 10^4

answer si 4.8*10^4
6 0
3 years ago
So I don't know to solve this <br>​
Kruka [31]

Answer:

A

Step-by-step explanation:

When a slope is undefined, it is always x = ?

The point (-5, -8) tells us that x = -5

Option A also has a point with x = -5

5 0
2 years ago
Please solve Questions - 18 , 20 , 21 <br>Show proper work. Thank-you!
Ymorist [56]
18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).

Answer: B]

20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3

21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]


3 0
3 years ago
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