Find the series in which5th term is 22/16 and 4th term is -4
1 answer:
Answer:
The series is given as follows;
Step-by-step explanation:
Assuming the series is an arithmetic progression, (AP), series, we have
The nth term of the desired series = a + (n - 1)×d
Where;
a = The first term
n = The position of the term in the series
d = The common difference
Given that the 5th term = 22/16 and the 4th term = -4, we have;
d = The difference between consecutive terms = Difference between the 5th term and the 4th term
∴ d = 22/16 - (-4) = 43/8 = 5.375
22/16 = a + (5 - 1)×5.375
∴ a = 22/16 - 4×5.375 = -20.625
The series is therefore;
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Answer:
y = 0.5x² +3x +5
Step-by-step explanation:
There are several ways to do this. The most straightforward may be to fill three table values into the equation and solve for a, b, c. Using the first three values, the equations would be ...
y = ax² + bx + c
- 0.5 = 9a -3b +c . . . . first point
- 1.0 = 4a -2b +c . . . . second point
- 2.5 = a -b +c . . . . . . third point
Solving this system of equations by your favorite method gives ...
a = 0.5, b = 3, c = 5
so the quadratic is ...
y = 0.5x² +3x +5
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Since you are given the y-intercept (0, 5), you know the constant in the equation is 5. The given table values are equally-spaced, so finding differences can be informative.
first differences: 1 -0.5 = 0.5; 2.5 -1 = 1.5; 5 -2.5 = 2.5; 8.5 -5 = 3.5
second differences: 1.5 -0.5 = 1; 2.5 -1.5 = 1; 3.5 -2.5 = 1
That is, second differences are 1, which value is double the "a" coefficient of the equation. So, we know the equation is ...
y = 0.5x² +bx +5
Filling in x=1, we get
8.5 = 0.5 +b +5
3 = b
and the equation is ...
y = 0.5x² +3x +5
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You can also let your graphing calculator or spreadsheet program show you a quadratic regression equation through these points. It gives the same result.
