Find the series in which5th term is 22/16 and 4th term is -4
1 answer:
Answer:
The series is given as follows;
Step-by-step explanation:
Assuming the series is an arithmetic progression, (AP), series, we have
The nth term of the desired series = a + (n - 1)×d
Where;
a = The first term
n = The position of the term in the series
d = The common difference
Given that the 5th term = 22/16 and the 4th term = -4, we have;
d = The difference between consecutive terms = Difference between the 5th term and the 4th term
∴ d = 22/16 - (-4) = 43/8 = 5.375
22/16 = a + (5 - 1)×5.375
∴ a = 22/16 - 4×5.375 = -20.625
The series is therefore;
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Final answer
Option B is the final answer
Answer:
C) The parabola is narrower and reflected across the x-axis.
Step-by-step explanation:
The original parabola has equation:
The transformed parabola has equation
How wide the graph is can be determined by the absolute value of the coefficient.
The smaller the absolute value of the coefficient, the wider the graph.
Since
The original graph is wider than the transformed graph.
Also the negative factor tells us there is a reflection in the x-axis.