Lets say pi is 3.14
The area of a circle is: pi*radius squared
The radius is half the diameter so it is 5 inches.
3.14*5 squared 2
3.14*25
78.5inches squared
Answer:
I dont understand what their asking but there are three problems I do know. 2x+5=19 is a equation A=2l+2w is an equation and 3w+4 is an expression.
Step-by-step explanation:
What can u send o pic of assignment
Answer:
i) 3*m*n + 7
Then we can write the first term as:
"3 times the product between two numbers"
Where the product of two numbers is m*n
And after that we need to add 7, then the complete sentence is:
"3 times the product between two numbers, increased by 7"
ii) x*y + (x + y)
The first part, x*y, can be written as:
"the product of two numbers"
where the two numbers are the number x and the number y.
After that, we add the sum of these two numbers, then the complete sentence can be:
"the product of two numbers, plus the sum of these two numbers"
Answer:
The width is 50 yards and the length is 141 yards.
Step-by-step explanation:
Let's call: L the length of the field and W the width of the field.
From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:
2L + 2W = 382
Because the perimeter of a rectangle is the sum of two times the length with two times the width.
Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:
L = 3W - 9
So, replacing this last equation on the first one and solving for W, we get:
2L + 2W = 382
2(3W - 9) + 2W = 382
6W -18 +2W = 382
8W - 18 = 382
8W = 382 + 18
8W = 400
W = 400/8
W = 50
Replacing W by 50 on the following equation, we get:
L = 3W - 9
L = 3(50) - 9
L = 141
So, the width of the rectangular field is 50 yards and the length is 141 yards.
