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Stels [109]
3 years ago
8

Which of the following lines is perpendicular to the x-axis and contains the point (-11.4, 12.8)

Mathematics
1 answer:
sergejj [24]3 years ago
7 0

The line x = -11.4 is perpendicular to the x-axis and contains point

(-11.4 , 12.8)

Step-by-step explanation:

Let us revise the equations of the vertical lines and horizontal lines

  • The vertical line is a line parallel to y-axis
  • The x-coordinates of all points lie on the line are equal
  • The equation of the vertical line basses through point (a , b) is x = a
  • The horizontal line is a line parallel to x-axis
  • The y-coordinates of all points lie on the line are equal
  • The equation of the horizontal line passes through point (a , b) is y = b
  • The vertical line and the horizontal line are perpendicular to each other when intersect each other

∵ The line is perpendicular to the x-axis

∴ The line is a vertical line

∴ The equation of the line is x = a, where a is the x-coordinate

   of any point lies on the line

∵ The line contains point (-11.4 , 12.8)

∵ The x-coordinate of the point is -11.4

∴ a = -11.4

∴ The equation of the line is x = -11.4

The line x = -11.4 is perpendicular to the x-axis and contains point

(-11.4 , 12.8)

Learn more:

You can learn more about the linear equation in brainly.com/question/13168205

#LearnwithBrainly

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Answer:

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 117, \sigma = 10.6, n = 6, s = \frac{10.6}{\sqrt{6}} = 4.33

What is the level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L ?

This is the value of X when Z has a pvalue of 1-0.01 = 0.99. So X when Z = 2.33.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

2.33 = \frac{X - 117}{4.33}

X - 117 = 2.33*4.33

X = 127.1

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

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