8. Given the radius and area of the circle, calculate the angle at the centre of the circle.
1 answer:
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Step-by-step explanation:
I'll do 2.
Alright,Alex let say we have factored a quadratic into two binomial, for example
If we set both of those equal to zero
We can used the zero product property in this case to find the roots of the quadratic equation.
This means that
This means we set each binomal equal to zero to find it root.
So our roots are negative 3/5 and negative 2/3 using zero product property
Answer:
<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>Step-by-step explanation:
We know
for any real value of <em>a</em>.
|a| = b > 0 - <em>two solutions: </em>a = b or a = -b
|a| = 0 - <em>one solution: a = 0</em>
|a| = b < 0 - <em>no solution</em>
<em />
|x + 6| - 4 = c
for c = 5:
|x + 6| - 4 = 5 <em>add 4 to both sides</em>
|x + 6| = 9 > 0 <em>TWO SOLUTIONS</em>
for c = -10
|x + 6| - 4 = -10 <em>add 4 to both sides</em>
|x + 6| = -6 < 0 <em>NO SOLUTIONS</em>
<em></em>
Calculate the solutions for c = 5:
|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9 <em>subtract 6 from both sides</em>
x = 3 or x = -15