Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
Answer:
A. {(1, 6.7), (2, 6.4), (3, 6.1)}
Step-by-step explanation:
The watering can dispenses water at a rate of 0.3 gallon per minute and the original volume of water in the can was 7 gallons.
Let y represent the volume of water in the can in gallons
Let x represent time in minutes
f(x) = y = 7 – 0.3(x)
When x = 1,
y = 7 – 0.3(1)
= 7 – 0.3
= 6.7
The pair will be (1, 6.7)
When x = 2,
y = 7 – 0.3(2)
= 7 – 0.6
= 6.4
The pair will be (2, 6.4)
When x = 3,
y = 7 – 0.3(3)
= 7 – 0.9
= 6.1
The pair will be (3, 6.1)
The set of ordered pairs shows the volume of water in the can in gallons (y) as a function of time in minutes (x) from the first minute after the can starts dispensing water is {(1, 6.7), (2, 6.4), (3, 6.1)}
Answer:
d. 540 deg
Step-by-step explanation:
2 pi radians = 360 deg
(360 deg)/(2pi rad) = 1
3 pi * (360 deg)/(2 pi rad) = 3 * 180 deg = 540 deg
25978.5964401. You can type it in a calculator and get the same answer!(:
Answer:
4(3y+8)
Step-by-step explanation:
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