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san4es73 [151]
3 years ago
10

What is an equation of the line that passes through the points (6, 1) and (-6, -1)?

Mathematics
1 answer:
ahrayia [7]3 years ago
3 0

Answer:

y =  \frac{1}{6} x

Step-by-step explanation:

The equation of a line can be written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

\boxed{gradient =  \frac{y1 - y2}{x1 - x2} }

Using the above formula,

m =  \frac{1 - ( - 1)}{6 - ( - 6)}  \\ m =  \frac{1 + 1}{6 + 6}  \\ m =  \frac{2}{12}  \\ m =  \frac{1}{6}

Substitute the value of m into the equation:

y =  \frac{1}{6} x + c

To find the value of c, substitute a pair of coordinates.

When x=6, y=1,

1 =  \frac{1}{6} (6) + c \\ 1 = 1 + c \\ c = 1 - 1 \\ c = 0

Thus, the equation of the line is y=⅙x.

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