If A(t) is the amount of salt in the tank at time t, then A(0) = 50 g and
A'(t) = (1 g/L)*(3 L/min) - (A(t)/120 g/L)*(3 L/min)
Multiply both sides by 
, so that the left side can be condensed as the derivative of a product:
Integrate both sides and solve for A(t).
Given that A(0) = 50 g, we have
so that the amount of salt in the tank at time t is
I made a number line and drew it out -6,-5,-4,-3,-2,-1,0,1,2 and i counted how many i had to move over to get to 2 from -6 and i got 8
Answer:
I think it is 100.5
Step-by-step explanation:
I say this because to get how many miles ann can go with one gallon of gas is 33.5 so if you x that by 3 it gets 100.5
The answer to your question is 4:10
