To find this answer, we subtract each of the like terms in the equation. 3x and 3x are like terms, -4y and 2y are like terms, and 7 and -5 are like terms. Now we subtract. 3x - 3x is 0, -4y - 2y is -6y, and 7 - (-5) is 12. That means that the result is -6y = 12, or B.
The central angle is 2 radians.
Step-by-step explanation:
Arc length of circle = 6.9813
Radius of circle = 4
Central angle = ?
The formula used to find central angle is :

where s= arc length, r = radius and Ф= central angle
We are given:
s= 6.9813 and r = 4 , finding central angle:

Rounding off to nearest whole number:

So, The central angle is 2 radians.
Keywords: Central angle of circle
Learn more about Central angle of circle at:
#learnwithBrainly
Answer:
1.4
Step-by-step explanation:
in the graph, the points are 14 points apart, when the step of the graph is set to .1, if you count, they're .14 point apart, or 1.4
Answer:
The diameter of the model is 14.4 inches.
Step-by-step explanation:
The Diameter of the moon = 2,160 miles
The scale on the model represents 1 in = 150 miles
Let the model represents k inches in 2,160 miles.
So, by the Ratio of Proportionality:

⇒
or, k = 14.4 inches
⇒On the scale 2160 miles is represented as 14.4 inches
Hence the diameter of the model is 14.4 inches.