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Ivan
3 years ago
8

There were n signers of the Declaration of Independence. The youngest was Edward Rutledge, who was x years old. The oldest was B

enjamin Franklin, who was y years old.
x is 25% of 104, 7 is 10% of y, and n is 80% of y. y is what percent of (n+y−x)?
Mathematics
2 answers:
Lady bird [3.3K]3 years ago
8 0

Answer:

y represents  70\% of (n+y-x)

Step-by-step explanation:

We know that

x=25\%(104)\\7=10\%y\\n=80\%y

Solving these expression we have

x=\frac{25}{100} 104=26\\7=\frac{10}{100}y \iff y=\frac{7(100)}{10}=70\\ n=\frac{80}{100}y=\frac{4}{5}(70)=56

Now, replacing these values in the given expression

(n+y-x)=56+70-26=100

Then, to know what percentage of (n+y-x) is y, we have to divide them

\frac{y}{n+y-x}=\frac{70}{100}=0.70 (or \ 70\%)

<h3>Therefore,</h3>

y represents  70\% of (n+y-x)

kap26 [50]3 years ago
7 0

Answer:

Step-by-step explanation:

x = 26

y = 70

n = 56

res = 56+70-26 = 30+70 =100

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The length, width, and height of a rectangular prism are in the ratio 3:2:1, respectively. What is the length of the prism if it
Arturiano [62]
The three numbers have to multiply to 48 in a ratio of 3:2:1
which would be 6:4:2
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6 0
3 years ago
There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In
Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

P(0.45

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

P(p>0.8)=P(z>z^*)

The z value is calculated as before:

z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0
2 years ago
-3 + 4x = 41<br> What's x
marusya05 [52]
Move the -3 to the other side which makes it 41 + 3 = 44

So now the equation looks like 4x=44

Now divide 44 by 4, equals 11

x=11
3 0
3 years ago
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If ∠BAC ≅ ∠DCA, is ABE ≅ CDE? Explain.
Tanzania [10]

Answer:

The answer is A.

Step-by-step explanation:

It is A because both sides match up except for the last pair, where they are the same. Hope this helped!

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The graph of F(x) can be flipped over a certain line to produce the graph of its inverse. What is the equation of that line?
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y=x
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