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Arturiano [62]
3 years ago
13

I forgot how to do this. Can someone tell me how?

Mathematics
2 answers:
Lisa [10]3 years ago
8 0
Hello there!

8 = |5 - x|

Then flip it

|-x + 5| = 8

Then solve for the absolute value

We know either -x + 5 = 8 or -x+5 = -8

Let's solve the first possibility,which is -x + 5 = 8

-x + 5 = 8

-x= 8 - 5

-x = 3
Remember that we cannot leave the variable with a negative sign. To turn it into a positive sign, we need to divide both sides by -1

-x/-1 = 3/-1

x= -3

Now let's solve the second possibility which is -x+ 5 = -8

-x + 5 = -8

-x = -8 - 5

-x = -13

again, we cannot leave it with the negative sign so we gonna do the same thing which is divide both sides by -1

-x/-1 = -13/-1

x = 13

Thus, the answer is x= -3 or x = 13

The correct answer is option D

Best of luck with your studies!
Katyanochek1 [597]3 years ago
7 0
Hey there, CrisisOnCats!

Absolute value is when any value that's inside the box, positive or negative, will always come out as positive.
For this one, you solve it as a normal equation, solving for x.
So, 8 = 5 - x
8-5 = 5-5 - x
3 = -x
x = -3
One value can be -3
To find the other value, just find any value that's equal to 8 when added or subtracted from 5, negative or positive.
We have 13 in this case.
5 - 13 is equals to -8 but since it's absolute value, it would be positive 8.
So, the answer is D

Thank you for using Brainly.
See you soon!
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\large\boxed{\text{No.}\ \dfrac{0.5}{1}\neq\dfrac{1}{1.5}\neq\dfrac{1.5}{2}}

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\text{Let}\\ a,\ b,\ c\ -\ \text{sides of a triangle ABC, where}\ a\leq b\leq c\\d,\ e,\ f\ -\ \text{sides of a triangle}\ DE F,\ \text{where}\ d\leq e\leq f.\\\\\triangle ABC\sim\triangle DE F\iff\dfrac{a}{d}=\dfrac{b}{e}=\dfrac{c}{f}\\\\/\text{corresponding sides are in proportion}/

\bold{WARNING !!!}\\\\\text{No triangle like QRS exists!}\\\\1 + 0.5 = 1.5 !!!\\\\\text{The sum of the lengths of the two shorter sides of the triangle}\\\text{must be greater than the length of the longest side.}

\text{Despite this, let's check the ratios}

\text{We have:}\\\\\triangle XYZ\to a=1,\ b=1.5,\ c=2\\\triangle QRS\to d=0.5,\ e=1,\ f=1.5

\text{Check:}\\\\\dfrac{d}{a}=\dfrac{0.5}{1}=0.5\\\\\dfrac{e}{b}=\dfrac{1}{1.5}=\dfrac{10}{15}=\dfrac{2}{3}\\\\\dfrac{f}{c}=\dfrac{1.5}{2}=\dfrac{15}{20}=\dfrac{3}{4}\\\\\dfrac{d}{a}\neq\dfrac{e}{b}\neq\dfrac{f}{c}\neq\dfrac{d}{a}

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3 years ago
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