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Arturiano [62]
3 years ago
13

I forgot how to do this. Can someone tell me how?

Mathematics
2 answers:
Lisa [10]3 years ago
8 0
Hello there!

8 = |5 - x|

Then flip it

|-x + 5| = 8

Then solve for the absolute value

We know either -x + 5 = 8 or -x+5 = -8

Let's solve the first possibility,which is -x + 5 = 8

-x + 5 = 8

-x= 8 - 5

-x = 3
Remember that we cannot leave the variable with a negative sign. To turn it into a positive sign, we need to divide both sides by -1

-x/-1 = 3/-1

x= -3

Now let's solve the second possibility which is -x+ 5 = -8

-x + 5 = -8

-x = -8 - 5

-x = -13

again, we cannot leave it with the negative sign so we gonna do the same thing which is divide both sides by -1

-x/-1 = -13/-1

x = 13

Thus, the answer is x= -3 or x = 13

The correct answer is option D

Best of luck with your studies!
Katyanochek1 [597]3 years ago
7 0
Hey there, CrisisOnCats!

Absolute value is when any value that's inside the box, positive or negative, will always come out as positive.
For this one, you solve it as a normal equation, solving for x.
So, 8 = 5 - x
8-5 = 5-5 - x
3 = -x
x = -3
One value can be -3
To find the other value, just find any value that's equal to 8 when added or subtracted from 5, negative or positive.
We have 13 in this case.
5 - 13 is equals to -8 but since it's absolute value, it would be positive 8.
So, the answer is D

Thank you for using Brainly.
See you soon!
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Answer:

4

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3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

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Answer:

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