Answer:
square with (-2,4) and (3,-1) vertices
There really is no single "obvious" choice here...
Possibly the sequence is periodic, with seven copies of -1 followed by six copies of 0, or perhaps seven -1s and seven 0s. Or maybe seven -1s, followed by six 0s, then five 1s, and so on, but after a certain point it would seem we have to have negative copies of a number, which is meaningless.
Or maybe it's not periodic, and every seventh value in the sequence is incremented by 1? Who knows?
I'll go ahead and assume the latter case, that the sequence is not periodic, since that's technically somewhat easier to manage. We can assign the following rule to the

-th term in the sequence:


for

.
So the generating function for this sequence might be

As to what is meant by "closed form", I'm not sure. Would this answer be acceptable? Or do you need to find a possibly more tractable form for the coefficient not in terms of the floor function?
Answer:
k12
Step-by-step explanation:
How many do you want ? There are an infinite number of them.
You can find a huge number of them with your calculator
Here are a few (2 for each point I'll earn):
5³ = 125
6³ = 216
7³ = 343
8³ = 512
9³ = 729
10³ = 1,000
11³ = 1,331
12³ = 1,728
13³ = 2,197
14³ = 2,744
.
.
etc.
Answer:
3^-5
Step-by-step explanation:
x^-3=1/x^3
this rule applies to all negative exponents lol