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3 years ago

Tiffany’s allowance is reduced $1.25 every time she forgets to clean her room.

Mathematics

1 answer:

snow_tiger [21]3 years ago

4 0

Answer:

$8.75 is your answer.

Step-by-step explanation:

What you do is you multiply 1.25 by 7.

1.25 x 7 = $8.75

$8.75 is your answer.

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The width of the rectangle is 75% of its length. (24 in.)

sashaice [31]

Answer:

Step-by-step explanation:

7 0

2 years ago

D. Rom has just given an insurance company $35,000. In return, he will receive an annuity of $3,700 for 20 years. At what

Feliz [49]

Answer:

0.53%

Step-by-step explanation:

hope it is well understood

4 0

2 years ago

Find the number of years it would take for $1,200 to earn simple interest of $324 at an annual interest rate of 6% per year.

nydimaria [60]

Years=100x S.I
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rate x principal

4 0

2 years ago

Math-- Farmer Bill has 500 meters of fencing and wants to enclose a rectangular plot that borders on a river. If farmer Bill doe

bixtya [17]

Answer:

Required dimensions of the rectangle are L = 200 m, W = 100 m

The largest area that can be enclosed is 20,000 sq m.

Step-by-step explanation:

The available length of the fencing = 500 m

Now, Perimeter of a rectangle = SUM OF ALL SIDES = 2(L+B)

But, here once side of the rectangle is NOT FENCED.

So, the required perimeter

= Perimeter of Complete field - Boundary of 1 open side

= 2(L+ W) - L = 2W + L

Now, fencing is given as 500 m

⇒ 2W + L = 500

Now, to maximize the length and width:

put L = 200, W = 100

we get 2(W) +L = 2(200) + 100 = 500 m

Hence, required dimensions of the rectangle are L = 200 m, W = 100 m

The maximized area = Length x Width

= 200 m x 100 m = 20, 000 sq m

Hence, the largest area that can be enclosed is 20,000 sq m.

6 0

2 years ago

The length of a rectangle is 3 inches more than the width. The area is 10 square inches. Find the dimensions

mr_godi [17]

Answer:

Width = 2

Length = 5

Step-by-step explanation:

let A be the area of the rectangle

L be the length of the rectangle

w be the width of the rectangle

Formula: ‘area of a rectangle’

A = L × w

…………………………………………………

A = L × w

⇔ 10 = (w + 3) × w

⇔ 10 = w² + 3w

⇔ w² + 3w - 10 = 0

Solving the quadratic equation w² + 3w - 10 = 0 :

Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49

then √Δ = 7

$\Longrightarrow w=\frac{-b+\sqrt{\Delta } }{2a} =\frac{-3+7}{2} =2$

$or\ w=\frac{-b-\sqrt{\Delta } }{2a} =\frac{-3-7}{2} =-5$

-5 is not valid ,because w represents the width

which must be a positive number

Then w = 2

Conclusion:

Width = 2

Length = 2 + 3 = 5

6 0

1 year ago