Question

Usha thinks that the area of the development will be greater than the total area of 50 football pitches.

Answer 1

Answer:

Usha is correct

Step-by-step explanation:

See attachment

Given

Dimension of the development

$Height = \frac{1}{2}\ mile$

$Base = \frac{1}{2}\ mile$

Dimension of a football field

$Length = 100m$

$Width = 50m$

First, we calculate the area of the development.

Because it is triangular in shape, the area is:

$Area = \frac{1}{2} * Height * Base$

$Area = \frac{1}{2} * \frac{1}{2}mile * \frac{1}{2}mile$

Convert mile to meter

$Area = \frac{1}{2} * \frac{1}{2}* 1600m * \frac{1}{2} * 1600m$

$Area = \frac{1}{2} * 800m * 800m$

$Area = 400m * 800m$

$Area = 320000m^2$

The area of 50 football pitch is then calculated as:

$Area = 50 * Length * Width$

$Area = 50 * 100m * 50m$

$Area = 250000m^2$

By comparison:

$320000 > 250000$

Hence, Usha's thought is correct