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cluponka [151]
3 years ago
13

What is an auxiliary line in Geometry​

Mathematics
1 answer:
Jlenok [28]3 years ago
3 0
It means an extra line needed to complete a proof/problem in plane geometry.
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Which of the following equations is in standard form?
swat32
D. 2x+3y=14 is the correct answer.
6 0
3 years ago
Read 2 more answers
A geographer found that the land area of Aruba is 75 square miles and the land area of Bermuda is 19 square miles. Based on thes
MakcuM [25]

The interpretation of<em> </em><em>x</em> in the equation 75•x + 19•y = T, used by the geographer, based on the land area of Aruba, 75 m², and Bermuda, 19 m², is the population in a square mile of Aruba

<h3>Which method can be used to find the interpretation of <em>x </em>in the equation?</h3>

The land area of Aruba = 75 m²

Land area of Bermuda = 19 m²

The total number of residents is given in the question by the equation;

75•x + 19•y = T

Therefore;

x = The number of people in a square mile in Aruba

y = The number of people in a square mile in Bermuda

Which gives;

  • The interpretation of the variable, <em>x </em>in the context is the population of Aruba per square mile.

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6 0
2 years ago
Use Gaussian elimination to write each system in triangular form
Feliz [49]

Answer:

To see the steps to the diagonal form see the step-by-step explanation. The solution to the system is x =  -\frac{1}{9}, y= -\frac{1}{9}, z= \frac{4}{9} and w = \frac{7}{9}

Step-by-step explanation:

Gauss elimination method consists in reducing the matrix to a upper triangular one by using three different types of row operations (this is why the method is also called row reduction method). The three elementary row operations are:

  1. Swapping two rows
  2. Multiplying a row by a nonzero number
  3. Adding a multiple of one row to another row

To solve the system using the Gauss elimination method we need to write the augmented matrix of the system. For the given system, this matrix is:

\left[\begin{array}{cccc|c}1 & 1 & 1 & 1 & 1 \\1 & 1 & 0 & -1 & -1 \\-1 & 1 & 1 & 2 & 2 \\1 & 2 & -1 & 1 & 0\end{array}\right]

For this matrix we need to perform the following row operations:

  • R_2 - 1 R_1 \rightarrow R_2 (multiply 1 row by 1 and subtract it from 2 row)
  • R_3 + 1 R_1 \rightarrow R_3 (multiply 1 row by 1 and add it to 3 row)
  • R_4 - 1 R_1 \rightarrow R_4 (multiply 1 row by 1 and subtract it from 4 row)
  • R_2 \leftrightarrow R_3 (interchange the 2 and 3 rows)
  • R_2 / 2 \rightarrow R_2 (divide the 2 row by 2)
  • R_1 - 1 R_2 \rightarrow R_1 (multiply 2 row by 1 and subtract it from 1 row)
  • R_4 - 1 R_2 \rightarrow R_4 (multiply 2 row by 1 and subtract it from 4 row)
  • R_3 \cdot ( -1) \rightarrow R_3 (multiply the 3 row by -1)
  • R_2 - 1 R_3 \rightarrow R_2 (multiply 3 row by 1 and subtract it from 2 row)
  • R_4 + 3 R_3 \rightarrow R_4 (multiply 3 row by 3 and add it to 4 row)
  • R_4 / 4.5 \rightarrow R_4 (divide the 4 row by 4.5)

After this step, the system has an upper triangular form

The triangular matrix looks like:

\left[\begin{array}{cccc|c}1 & 0 & 0 & -0.5 & -0.5  \\0 & 1 & 0 & -0.5 & -0.5\\0 & 0 & 1 & 2 &  2 \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right]

If you later perform the following operations you can find the solution to the system.

  • R_1 + 0.5 R_4 \rightarrow R_1 (multiply 4 row by 0.5 and add it to 1 row)
  • R_2 + 0.5 R_4 \rightarrow R_2 (multiply 4 row by 0.5 and add it to 2 row)
  • R_3 - 2 R_4 \rightarrow R_3(multiply 4 row by 2 and subtract it from 3 row)

After this operations, the matrix should look like:

\left[\begin{array}{cccc|c}1 & 0 & 0 & 0 & -\frac{1}{9}  \\0 & 1 & 0 & 0 &   -\frac{1}{9}\\0 & 0 & 1 & 0 &  \frac{4}{9} \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right]

Thus, the solution is:

x =  -\frac{1}{9}, y= -\frac{1}{9}, z= \frac{4}{9} and w = \frac{7}{9}

7 0
3 years ago
If Rita receives $45.34 interest for a deposit earning 4% simple interest for 160 days, what is the amount of her deposit? (Roun
vovangra [49]

Answer:

6.4

Step-by-step explanation:

5 0
3 years ago
Compute delta y/delta x for the interval [2,5], where y = 4x - 9.
Kamila [148]
We have to compute: Δ y / Δ x.
The interval is [ 2, 5 ] and y = 4 x - 9.
y 1 = 4 · 2 - 9 = 8 - 9 = - 1
y 2 = 4 · 5 - 9 = 20 - 9 = 11
Δ y / Δ x = ( y 2 - y 1 ) / ( x 2 - x 1 ) =
= ( 11 - ( - 1 ) ) / ( 5 - 2 ) = ( 11 + 1 ) / 3 = 12 / 3 = 4
Answer:
Δ y / Δ x = 4

3 0
3 years ago
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