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777dan777 [17]
3 years ago
15

Find a polynomial, which if substituted for M will make the equation an identity: M + (5x2 –2xy) = 6x2 +9xy–y2

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
7 0

Answer:

M=x^2+11xy-y^2

Step-by-step explanation:

To find M you have to subtract.

6x^2+8xy-y^2-(5x^2-2xy)

6x^2+9xy-y^2-5x^2+2xy

6x^2+11xy-y^2-5x^2

x^2+11xy-y^2

Gennadij [26K]3 years ago
5 0

Answer: you just solve for M

M = x^2 + 11xy – y^2


Step-by-step explanation:

M + (5x^2 –2xy) = 6x^2 +9xy–y^2

M = 6x^2–5x^2 + 9xy+2xy – y^2

M = x^2 + 11xy – y^2


Check:

x^2 + 11xy – y^2 + 5x^2 – 2xy

6x^2 + 9xy – y^2

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Maura writes an expression equivalent to 8a - (-3 - 5a) - 2a. Her work is in the picture. In what step does Maura make a mistake
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11a + 3

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Help! given 2(x-9)=-10 prove x=4 with statements and reasons
Sedbober [7]

Step-by-step explanation:

<u>Proof:</u>

<em>2</em><em> </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>9</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em> </em><em>1</em><em>0</em><em> </em><em> </em><em>when </em><em>x </em><em>=</em><em> </em><em>4</em>

<em>2</em><em> </em><em>(</em><em> </em><em>4</em><em> </em><em>-</em><em> </em><em>9</em><em>)</em><em> </em><em>=</em><em> </em><em>-</em><em>1</em><em>0</em>

<em>8</em><em> </em><em>-</em><em> </em><em>1</em><em>8</em><em> </em><em>=</em><em> </em><em>-</em><em>1</em><em>0</em>

<em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u> </u></em><em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u> </u></em>..........hence proven

<u>Reasons </u>

- When you replace X with 4, you can clearly see that the equation is equal to -10.

sorry I couldn't answer accurately, but I hope this helps

8 0
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7x what gives me 1 can someone answer I'm new
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Doing (7x÷7) I think equals 1
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