<u>M</u><u>e</u><u>t</u><u>h</u><u>o</u><u>d</u><u> </u><u>1</u><u> </u><u>:</u>
replace x and y by their value 1 and 3
3 = 4(1) - 1 = 4-1 = 3
2(1) + 3 = 2 + 3 = 5
correct
<u>M</u><u>e</u><u>t</u><u>h</u><u>o</u><u>d</u><u> </u><u>2</u><u> </u><u>:</u>
y = 4x - 1
2x + y = 5
y = 4x - 1
y = -2x + 5
y - y = 4x - 1 - ( -2x + 5 )
0 = 4x - 1 + 2x - 5
6x - 6 = 0
6x = 6
x = 6/6 = 1
y = 4x - 1
y = 4(1) - 1
y = 3
correct
Step One
======
Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
6:10
The simplest form would be 3:5.
2500 kg x 4 weeks =10000kg
<span>1 ton = 907.2 kg
??=10000kg
1 x 10000 divided by 907.2
answer=11 tones </span>
Answer:
Step-by-step explanation:
The computation is shown below:
The numbers of possible results at the time when we drawing in two tries is 9
i.e. shown below:
11, 12, 13, 21, 22, 23, 31, 32, 33
Now the probability is
