Answer: The length of the second arc is 12 feet.
Step-by-step explanation:
Since we know that
A rope is swinging in such a way that the length of the arc is decreasing geometrically,
Length of first arc = 18 feet
Length of third arc = 8 feet
Let the length of second arc be x
As we know that
Hence, the length of the second arc is 12 feet.
We can compare 2 fractions by means of the cross multiplication method. In our case, we have
since 50 is greater than 24 then 10/12 is greater than 2/5:
Answer:
y-10=2/3(x-8)
Step-by-step explanation:
(y2-y1)/(x2-x1) is the equation for slope so put your points in you get 2/3 once simplified then its just a matter of putting points in the equation y-y1= m(x-x1)
Step One
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Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
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Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Answer:
111°
Step-by-step explanation:
- All these are parallel lines, so the 36° angle is equal to the 36° angle inside the big triangle because they are vertically opposite.
- Ignore the line cutting between 45° and the 30° and consider it as one triangle
- Add them to get 75°
- Now you have two known angles 75° and 36°
- To get angle <em>x</em><em> </em>add 75° and 36° to get 111°
- Because x° is an exterior angle and exterior angles equal to the sum of interior angles opposite it inside the triangle.
