R = 11-2m
S = n+5
T = -m-3n+8
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Add up S and T to get...
S+T = (n+5)+(-m-3n+8)
S+T = n+5-m-3n+8
S+T = -m+(n-3n)+(5+8)
S+T = -m+(1n-3n)+(5+8)
S+T = -m+(-2n)+(13)
S+T = -m-2n+13
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Subtract that result from R
R - [S + T]
11-2m - [-m-2n+13]
11-2m +m+2n-13
(-2m+m) + (2n) + (11-13)
(-2m+1m) + (2n) + (11-13)
(-1m) + (2n) + (-2)
-m + 2n - 2
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The final answer is -m + 2n - 2
multiply 12 and 16 then multiply 8 and 10 then add them up to get 15,360
Answer:
a
b
Step-by-step explanation:
From the question we are told that
The number of bootstrap samples is n = 1000
From the question we are told the confidence level is 95% , hence the level of significance is
=> 
Generally the percentage of values that must be chopped off from each tail for a 95% confidence interval is mathematically evaluated as
=>
Generally the number of the bootstrap sample that must be chopped off to produce a 95% confidence interval is
=> 
=>
Answer:
Exact probability = 1/7
(Approximate probability = 0.142857)
========================================================
Explanation:
There are three 5 dollar bills out of 7 total. The probability of selecting a five dollar bill is 3/7. Let A = 3/7 since we'll use it later.
After the first selection is made, we have 3-1 = 2 five dollar bills left out of 7-1 = 6 bills overall. This is assuming we do not put the first selection back, or replace it with another five dollar bill.
The probability of selecting another five dollar bill is 2/6 = 1/3. Let B = 1/3.
Multiply the values of A and B to get
A*B = (3/7)*(1/3) = (3*1)/(7*3)= 1/7
Note the 3's divide and cancel out.
Using a calculator, 1/7 = 0.142857 approximately
It’s 9 cause 9x3=27
hhhhhhhhhhhhhhhhh
