Title:
<h2>The revenue will be maximum for 253 passengers.</h2>
Step-by-step explanation:
Let, the number of passenger is x, which is more than 194.
In this case, the travel agency will charge [312 - (x - 194)] per passenger.
The total revenue will be ![x[312 - (x - 194)] = 506x - x^{2}](https://tex.z-dn.net/?f=x%5B312%20-%20%28x%20-%20194%29%5D%20%3D%20506x%20-%20x%5E%7B2%7D)
.
As x is the variable here, we can represent the revenue function by R(x). Hence, 
.
The revenue will be maximum when 
.
Answer:
I don't understand the instructions, but I'll answer the question in the picture.
The angle next to 52 is vertical to y, so, 90-52=y.
Thus, y=38
The range of the given relation is D. R = {-1, 3, 5, 8}.
Step-by-step explanation:
Step 1:
The range of a relation is the second set of values while the domain constitutes the first set of values.
There are 4 given relations with two sets of values so there would be 4 domain values and 4 range values.
Step 2:
The range of (1, -1) = -1,
The range of (2, 3) = 3,
The range of (3, 5) = 5,
The range of (4, 8) = 8.
Combining these values we get the range as {-1, 3, 5, 8} which is option D.
Answer:
0.84 square in
Step-by-step explanation:
Since the capacity of the cable is proportional to its cross-sectional area. If a cable that is 0.3 sq in can hold 2500 lb then per square inch it can hold
2500 / 0.3 = 8333.33 lb/in
To old 7000 lb it the cross-sectional area would need to be
7000 / 8333.33 = 0.84 square in
