Answer:
(1, 1), (2, 2), (-3, -3), (4, 4), (-5, -5)
Step-by-step explanation:
You get a straight line. As you can see in the picture, the figure lies in the first and third quadrant.
Heya !
Using a theoram about triangles ,
Given a triangle ∆ABC, the sum of the lengths of any two sides of the triangle is greater than the length of the third side ,
Also , the length of third side always greater than absolute difference of the other two sides ,
Let the third side be x ,
So , x < 9 + 8 and x > 9 - 8
x < 17 and x > 1
Hence , x ∈ [ 2 , 17 ] inch.
Above case is true for any triangle , be it scalene , Isosceles , Right-angled ...
As , for Isosceles , the third side can be 8 or 9 inches ,
For scalene , all values in the above range satusfies ,
For right angled triangle , we have 2 cases ,
Case 1 : Third side is the hypotenuse
Then , x = √(9²+8²) = √145 = 12.0415 inch.
Case 2 : Third side is not the hypotenuse
Then , x = √(9²-8²) = √17 = 4.1231 inch.
Hope it helps you ! :)
n+6=6nStep-by-step explanation:
Answer:
A: 6 boxes right, 9 boxes down, 9 boxes left, connect back to start.
B: 3 boxes right, 9 boxes up, (diagonal 6 right, 12 down), 9 boxes up, 6 boxes right.
C: 1 box right, 2 boxes down, 1.5 boxes right, 1 box up, .5 box right, 2.5 boxes down, 3 boxes left, 3.5 boxes up to connect.
D: (diagonal 1 up, 1 right), 1 box right, (diagonal 1 down, 1 right), 1 box down, (diagonal 3 down, 3 left), 3 boxes left
Step-by-step explanation:
