Answer:
length = 32cm; width = 20cm
Step-by-step explanation:
The answer to the question above is provided thus.
Formula for calculating the perimeter of a rectangle = 2(l + w)
Where,
l = length
w = width
Recall that perimeter is 104 cm and length is 12cm longer than the width.
Thus,
P = 2(l + w)
Since perimeter is 2 times l + w, we divide through by 2 to get l + w. That is:
Dividing through by 2
since length is length is 12cm longer than the width, we think of two numbers whose sum equals 52 and difference equals 12. The numbers are 32 and 20. That is, 32 + 20 = 52; 32 - 20 = 12.
Therefore,
104cm = 2( 32cm + 20cm)
Hence, length is 32cm while width is 20cm. The length is 12cm longer than the width such that 32cm - 20cm = 12cm.
Thus, the dimension of the rectangle whose perimeter is 104cm is 32cm + 20 cm or 32cm and 20cm.
Check,
Perimeter of a rectangle = 2( l + w)
104cm = 2( 32cm + 20cm)
104cm = 2(52cm)
104cm = 2 × 52cm
104cm = 104cm
Length is 12cm longer than the width
32cm - 20cm = 12cm
Answer:
NO SOLUTION
Step-by-step explanation:
We can make this problem easier to understand if we write the system vertically:
2x-y=7
y=2x+3
and then rewrite the first problem in the form y = mx + b:
2x-y=7 ↔ y + 7 = 2x ↔ y = 2x + 7
y=2x+3
Note how these two equations have the same slope, but different y-intercepts. This tells us that the two lines are parallel, which in turn tells us that they never intercept one another.
Thus, this system has NO SOLUTION.
100% (full) - 12.5% = 87.5% more needed.
25gallons x 87.5% = 21.875 gallons
Answer: 21.875 gallons
Answer:
i guess Bis the answer bcuz, A sample space is a collection or a set of possible outcomes of a random experiment
Answer:
HOPE IT HELPS PLZ MARK ME BRAINLIEST
Step-by-step explanation:
A={1,2,3,4,5,6}
R={(x,y):y is divisible by x}
We know that any number (x) is divisible by itself.
(x,x)∈R
∴R is reflexive.
Now,(2,4)∈R [as 4 is divisible by 2]
But,(4,2)∈
/
R. [as 2 is not divisible by 4]
∴R is not symmetric.
Let (x,y),(y,z)∈R. Then, y is divisible by x and z is divisible by y.
∴z is divisible by x.
⇒(x,z)∈R
∴R is transitive.
Hence, R is reflexive and transitive but not symmetric.
