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anastassius [24]
3 years ago
15

How do you slove Isaiah also wants to plant peppers in2/6 of the garden.he also wants to plant cucumbers in 2/6.He also wants to

plant corn in3/6 of the garden.Can he plant the vegetables this way?Explain.
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
4 0
No he can't for the garden can not hold the vegetables
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In February, Ronald. Read a book that was 98 pages long. In March, he read a book that was 124 pages long. In April, he read a b
tester [92]

Answer:

430

Step-by-step explanation:

You add 98+124 which is 222 then add it plus 208 which is 430

7 0
3 years ago
Read 2 more answers
A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w
DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 21.5, \sigma = 4.7

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.175*4.7

X = 27.0225

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.04*4.7

X = 26.388

The lowest score that would meet the colleges requirement would be decreased to 26.388.

6 0
3 years ago
7. Tariq can play 18 holes of golf in 180 minutes. Calculate what is his average rate per hole?
Murljashka [212]
The avarage is 180:18=10 , 10 min per hole
7 0
2 years ago
Logan saves $5.50 in dimes and quarters over a week. He has 20 more dimes than quarters. Find the number of dimes and quarters h
Sveta_85 [38]
10 quarters 30 dimes
7 0
2 years ago
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I’d appreciate any help please!!! 30 points
Aliun [14]
7. 3c+3=84
3c=81
c=27
So either 81/3 but if simplified its 27/1

8. The correct answer would be 55=31+t
8 0
3 years ago
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