Answer:
there is none prime factorization of 3. Since it cant be multiplied by anything to get 3 like 2 and 5 and 7
Step-by-step explanation:
Step-by-step explanation:
To find the formula for the nth term ,
First , find the common difference or common ratio.
Common difference =
![T_2-T_1 \\ - 2 - 3 \\ = - 5](https://tex.z-dn.net/?f=T_2-T_1%20%5C%5C%20%20-%202%20-%203%20%5C%5C%20%20%3D%20%20-%205)
Common ratio =
![T_2/T_1 \\ \frac{ - 2}{3}](https://tex.z-dn.net/?f=T_2%2FT_1%20%5C%5C%20%20%5Cfrac%7B%20-%202%7D%7B3%7D%20)
The common difference applies to the other given numbers for example :
![T_3- T_2 = - 7 - ( - 2) \\ = - 7 + 2 = - 5](https://tex.z-dn.net/?f=T_3-%20T_2%20%20%3D%20%20-%207%20-%20%28%20-%202%29%20%5C%5C%20%20%3D%20%20-%207%20%2B%202%20%3D%20%20-%205)
this proves that it is an arithmetic sequence and the given formula for the nth term of an arithmetic sequence is
T_n =a(n-1)d
Where n = no of terms
a= first term
d= common difference
Answer:
a) see the plots below
b) f(x) is exponential; g(x) is linear (see below for explanation)
c) the function values are never equal
Step-by-step explanation:
a) a graph of the two function values is attached
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b) Adjacent values of f(x) have a common ratio of 3, so f(x) is exponential (with a base of 3). Adjacent values of g(x) have a common difference of 2, so g(x) is linear (with a slope of 2).
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c) At x ≥ 1, the slope of f(x) is greater than the slope of g(x), and the value of f(x) is greater than the value of g(x), so the curves can never cross for x > 1. Similarly, for x ≤ 0, the slope of f(x) is less than the slope of g(x). Once again, f(0) is greater than g(0), so the curves can never cross.
In the region between x=0 and x=1, f(x) remains greater than g(x). The smallest difference is about 0.73, near x = 0.545, where the slopes of the two functions are equal.
C. octagon but even though u dont have no picture
-6 (-v^3 - 3 + 5x^2) =
6v^3 + 18 - 30x^2 <==