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Rzqust [24]
3 years ago
7

Evaluate sin^2Θ, for Θ=45°

Mathematics
2 answers:
AleksAgata [21]3 years ago
6 0

Answer:

The answer to this is \frac{1}{2}

Step-by-step explanation:

I did the assignment, hope it helps! :)

Zielflug [23.3K]3 years ago
3 0

Answer:

sin^2(45) = (√2/2)^2 = 1/2

Step-by-step explanation:

sin2x = sin2 * x = 0.909x

sin(2(45)) = sin90 = 1

Hope this helps.

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Round each number to the place of the underlined digit.
miv72 [106K]

9514 1404 393

Answer:

  11) 14

  12) 390

  13) 0.5

  14) 497

  15) 496

  16) 1857.21

Step-by-step explanation:

If the digit to the immediate right of the underlined digit is 5 or greater, then the underlined digit is increased by 1 (carrying to higher digits, if necessary). Digits to the right of the underline digit are dropped, or replaced with zero (if they are left of the decimal point).

8 0
3 years ago
Let X1, . . . ,Xn ∈ R be independent random variables with a common CDF F0. Let Fn be their ECDF and let F be any CDF. If F = Fn
Georgia [21]

Answer:

See the proof below.

Step-by-step explanation:

For this case we need to proof that: Let X_1, X_2, ...X_n \in R be independent random variables with a common CDF F_0. Let F_n be their ECDF and let F any CDF. If F \neq F_n then L(F)

Proof

Let z_a different values in the set {X_1,X_2,...,X_n}} and we can assume that n_j \geq 1 represent the number of X_i that are equal to z_j.

We can define p_j = F(z_j) +F(z_j-) and assuming the probability \hat p_j = \frac{n_j}{n}.

For the case when p_j =0 for any j=1,....,m then we have that the L(F) =0< L(F_n)

And for the case when all p_j >0 and for at least one p_j \neq \hat p_j we know that log(x) \leq x-1 for all the possible values x>0. So then we can define the following ratio like this:

log (\frac{L(F)}{L(F_n)}) = \sum_{j=1}^m n_j log (\frac{p_j}{\hat p_j})

log (\frac{L(F)}{L(F_n)}) = n \sum_{j=1}^m \hat p_j log(\frac{p_j}{\hat p_j})

log (\frac{L(F)}{L(F_n)}) < n\sum_{j=1}^m \hat p_j (\frac{p_j}{\hat p_j} -1)

So then we have that:

log (\frac{L(F)}{L(F_n)}) \leq 0

And the log for a number is 0 or negative when the number is between 0 and 1, so then on this case we can ensure that L(F) \leq L(F_n)

And with that we complete the proof.

8 0
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