Answer:
The new coordinates of the points of the line segment are p'(2,1) and q'(3,4)
Step-by-step explanation:
we know that
When you reflect a point across the line y= x, the x-coordinate and y-coordinate change places.
so
The rule of the reflection of a point across the line y=x is
(x,y) -----> (y,x)
we have
Points p(1,2) and q(4,3)
Applying the rule of the reflection across the line y=x
p(1,2) ------> p'(2,1)
q(4,3) -----> q'(3,4)
therefore
The new coordinates of the points of the line segment are p'(2,1) and q'(3,4)
2x=5 so 5÷2 = x (2.5)
3y = 4 so 4÷3 = y (1.3 recurring)
4z = 3 so 3÷4 = z (0.75)
implement: 24x2.5x1.3•x0.75
hope i answered right
Answer I think A
Step-by-step explanation:
Answer:
-23
Step-by-step explanation:
We are given the functions;
h(x) = 5x - 3 and j(x) = -2x
Now, we want to find h[j(2)]
j(2) = -2(2)
j(2) = -4
Thus;
h(-4) = 5(-4) - 3
h(-4) = -20 - 3
h(-4) = - 23