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3 years ago

Blocks numbered 0 through 9 are placed in a box, and a block is randomly picked.

2 answers:

3 0

<span>Blocks numbered 0 through 9 are placed in a box, and a block is randomly picked.=3/10

</span><span>The probability of picking an odd prime number is . The probability of picking a number greater than 0 that is also a perfect square is=3/10</span>

faust18 [17]3 years ago

3 0

Answer: 2/5 and 3/10

Step-by-step explanation: Sample space S={0,1,2,3,4,5,6,7,8,9}

A:event of picking a odd prime number={1,3,5,7}

P(A)=4/10

=2/5

B: event of picking a number greater 0 that is also a perfect square={1,4,9}

P(B)=3/10

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A rectangle that is 2 inches by 3 inches has been scaled by a factor of 7.

loris [4]

Answer:

$New\ Lengths = (14,21)$

$New\ Scale\ Factor = \frac{1}{7}$

Step-by-step explanation:

Given

Rectangle:

Length = 2 in

Width = 3 in

Scale Factor = 7

Solving (a):

The side lengths of the new scale is calculated as follows;

New Lengths = Old Lengths * Scale Factor

$New\ Lengths = (2,3) * 7$

$New\ Lengths = (2 * 7,3* 7)$

$New\ Lengths = (14,21)$

Solving (b): To go back to the original length

Given that the initial scale factor is 7;

The new scale factor is the reciprocal of the old factor;

Hence;

$New\ Scale\ Factor = \frac{1}{7}$

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3 years ago

The table represents the speed of Frog A at a frog-jumping contest. Frog B travels 2 feet each second. If the course is 20 feet

Black_prince [1.1K]

Answer:

Frog b

Step-by-step explanation:

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3 years ago

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svetlana [45]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$1)\, XY=XZ$ Given

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$\displaystyle 3) \text{ $m\angle Y=m\angle XYQ + \angle QYZ$}$ Angle Addition

$\displaystyle 4)\text{ $YQ$ bisects $\angle XYZ$}$ Given

$5) \text{ $m\angle XYQ=m\angle QYZ$}$ Definition of Bisector

$\displaystyle 6)\text{ $m\angle Y=2m\angle QYZ$}$ Substitution

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$8)\text{ $ZP$ bisects $\angle XZY$}$ Given

$\displaystyle 9) \text{ $m\angle XZP=m\angle PZY$ }$ Definition of Bisector

$\displaystyle 10) \text{ $ m\angle Z = 2m\angle PZY $}$ Substitution

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$12)\text{ }m\angle QYZ=m\angle PZY$ Division Property of Equality

$13)\text{ } YZ=YZ$ Reflexive Property

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$15)\text{ } YQ=ZP$ CPCTC

*For clarification:

∠Y = ∠Z

YZ = YZ (or ZY)

∠PZY = ∠QYZ

So, Angle-Side-Angle Congruence:

ΔYZP is congruent to ΔZYQ

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3 years ago

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jeka94

Roses: 16
Total Cost: $20.64

Divide:
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Dvinal [7]

Answer:

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Step-by-step explanation:

I don't understand the answer choices, but supplementary angles add up to 180°. It looks like the third option is correct.

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