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Gelneren [198K]
3 years ago
15

Please I need the answers if it is for today please if you can in edited photography, it is before 9 o'clock At that time I have

to go to sleep please, I give a crown :(​

Mathematics
1 answer:
LenaWriter [7]3 years ago
4 0

Answer:

mkhhikbyjhggfikmnikkfyujikok

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Explain how the sign of a in the equation y=a(x-h)^2 + k tells you whether the parabola has a minimum or maximum value.
Svet_ta [14]
In short, for a vertical parabola, namely one whose independent variable is on the x-axis, usually is x², if the leading term coefficient is negative, the parabola opens downward, and its peak or vertex is at a maximum, check the picture below at the left-hand-side.

and when the leading term coefficient is positive, the parabola opens upwards, with a minimum, check the picture below at the right-hand-side.

8 0
3 years ago
Ordered pairs satisfy the equation 3y−9x=9
dalvyx [7]

Answer:

9

Step-by-step explanation:

3 (6)-9 (1)=9

18-9=9

i think that is the answer

6 0
3 years ago
the length of a pool 2 km long is represented on a map with a length of 20cm. what is the map scale used?​
goldenfox [79]

Answer:

The scale used is 1: 10,000 cm.

Step-by-step explanation:

Given that the length of a pool 2 km long is represented on a map with a length of 20cm, to determine what is the map scale used the following calculation must be performed:

2 km = 2,000 m

1m = 100cm

2,000 x 100 = 200,000

20: 200,000

10: 100,000

1: 10,000

Thus, the scale used is 1: 10,000 cm.

4 0
3 years ago
Read 2 more answers
The product of two mixed numbers that are each between 4 and 5 is between 16 and 25 true or false
Leni [432]

9514 1404 393

Answer:

  True

Step-by-step explanation:

The smallest the product could be is 4×4 = 16.

The largest the product could be is 5×5 = 25.

The product must be between 16 and 25. (true)

5 0
3 years ago
How do I solve this?
Crazy boy [7]

Answer:

71°

142°

Step-by-step explanation:

\because QS \: is \: the \: bisector \: of \:  \angle \: PQR\\\therefore m\angle RQS =m\angle PQS\\\because m\angle RQS = 71\degree...(given) \\ \huge \red{ \boxed{\therefore m\angle PQS = 71\degree}} \\   \because \: m\angle \: PQR = m\angle PQS  + m\angle RQS \\ \because \: m\angle \: PQR = 71\degree +  71\degree \\  \huge \purple{ \boxed{\therefore \: m\angle \: PQR = 142\degree}}

7 0
3 years ago
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