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Lynna [10]
3 years ago
13

36/9+2/9 fraction adding!!!

Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0

Answer: 38/9

Step-by-step explanation: Because the fractions presented already have common denominators, the only thing you need to do in order to solve the problem is add the numerators. 36+2= 38, and you keep your denominator the same when adding fractions (when they are the same).

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The graph shows 2 outliers. The scatter plot consist on a straight pattern. As seen, only 2 points are not within the straight line. We can conclude that only two points are outliers. =

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Which expressions are equivalent<br> to 1/81 ? check all that apply.<br> picture provided
Taya2010 [7]

{8}^{ - 1}  =  \frac{1}{8}

8-¹ ❌

{9}^{ - 2}  =  \frac{1}{ {9}^{2} }  =  \frac{1}{81}

9-² ✔️

\frac{ {9}^{8} }{ {9}^{4} }  =  {9}^{8 - 4}  =  {9}^{8}

9^8/9^4 ❌

\frac{9 {}^{8} }{ {9}^{10} }  =  {9}^{8 - 10}  =  {9}^{ - 2}  =  \frac{1}{9 {}^{2} }  =  \frac{1}{81}

9^8/9^10 ✔️

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9^-6 . 9³ ❌

{9}^{5} . \:  { 9}^{ - 7}  =  {9}^{5 - 7}  = 9 {}^{ - 2}  =  \frac{1}{ {9}^{2} }  =  \frac{1}{81}

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4 0
3 years ago
Please please help please
il63 [147K]

Answer:

6 times larger

Step-by-step explanation:

First, find the area of both.

Mary: 4*5.5=22

Lisa: 24*5.5=132

Then find what multiplied by 22 would equal 132. This is easy because it's a multiple-choice question.

22*20=440, so A is incorrect

We already know they are not equal, so then B can be crossed out

22*3=66, C would be incorrect

Leaving the only choice left to be the correct answer

22*6=132

4 0
3 years ago
the amusement park also has water rides 30% of the 80 rides are water-related how many water-related rides does the park have
sergejj [24]

Answer:

24.

Step-by-step explanation:

So you need to fine 30% of 80.

I did the following method:

-Break it down, and do, 80 -/- 10 which is 8, now you have 10%, and you need to find 30, times your 10% by 3, so 24.

-Therefore, 24 out of 80 rides at the amusement park are water-related.


Hope this helps!

--Emilie Xx


5 0
3 years ago
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