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iren [92.7K]
4 years ago
15

Use the above figure to answer the question. What’s the angle between the tangents at T in the figure?

Mathematics
1 answer:
UkoKoshka [18]4 years ago
6 0
The answer is 60 degrees
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Step-by-step explanation:

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F(x) = 2x^2<br> Find f(-6)
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Step-by-step explanation:

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4 years ago
If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?
Keith_Richards [23]
\bf \begin{cases}&#10;f(x)=2-x^{12}\\&#10;g(x)=x^2-9\\&#10;g(x)\div f(x)=\frac{g(x)}{f(x)}&#10;\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\&#10;-------------------------------\\\\&#10;\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}

so, the domain is all real numbers EXCEPT that one.
4 0
3 years ago
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