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WARRIOR [948]
3 years ago
7

To borrow​ money, you pawn your guitar. Based on the value of the​ guitar, the pawnbroker loans you ​$960. One month​ later, you

get the guitar back by paying the pawnbroker ​$1170. What annual interest rate did you​ pay?
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

The money was paid at an annual interest of 261.42%

Explanation:

  • The initial amount of the guitar when it was loaned was $960. After a month the guitar cost $1,170. This means that in one month the price went from $960 to $1,170.                                                                               Increase in cost = Difference between two costs = $1,170 - $960 = $210.
  • To convert this into a percent we divide the difference in value by the original price and multiply the answer with 100 to convert it into a percentage.                                                                                                      % increase in cost = difference between two costs / original cost                                                                                           % increase in cost = ($210 / $960) * 100 = 0.21785 * 100 = 21.785%
  • This 21.875% was the monthly interest that was paid. To convert it into annual interest rate we multiply it with the 12 months.
  • Annual interest rate = monthly interest rate * 12 = 21.785% * 12 = 261.42%. This means if the guitar was loaned for a year, you would have to pay $3469.44.
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muminat

Total number of 10 grader students = 260 students.

Total number of students who rides the bus and they are of 10th grader = 150 students.

Probability (a student rides the bus given that they are a 10th grader) =\frac{Total \ number \ of \ students \ rides \ the \ bus \ and \ 10th \ grader}{Total \ number \ of \ 10 \ grader \ students}

Therefore,

P(E) = \frac{150}{260}

Dividing top and bottom by 10, we get

P(E) = 15/26.

In decimals 0.577.

Therrefore, correct option is C) 150/260 = 15/26 = .577.

8 0
3 years ago
Which expressions represent rational numbers? select all the apply. startroot 100 endroot startroot 100 endroot 13.5 startroot 8
zlopas [31]

The expressions are irrational 1/3 + √216 and √64+ √353 and the expressions √100 × √100, 13.5 + √81, √9 + √729, and 1/5 + 2.5 are rational number.

<h3>What is a rational number?</h3>

If the value of a numerical expression is terminating then they are the rational number then they are called the rational number and if the value of a numerical expression is non-terminating then they are called an irrational number.

1.  √100 × √100

→ √100 × √100

→ 10 × 10 = 100

This is a rational number.

2.  13.5 + √81

→ 13.5 + √81

→ 13.5 + 9 = 22.5

This is a rational number.

3.  √9 + √729

→ √9 + √729

→ 3 + 27 = 30

This is a rational number.

4.  √64+ √353

→ √64 + √353

→ 8 + √353

This is an irrational number.

5.  1/3 + √216

→ 1/3 + √216

→ 1/3 + √216

This is an irrational number.

6.  1/5 + 2.5

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→ 0.2 + 2.5 = 2.7

This is a rational number.

More about the rational number link is given below.

brainly.com/question/9466779

7 0
2 years ago
Kim and Melody are selling popcorn buckets for a school fundraiser. Customers can buy small buckets or large buckets. Kim sold 3
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Answer:

The cost of

A small bucket = x = $8

A Larger bucket = y = $13

Step-by-step explanation:

Let the cost of

A small bucket = x

A Larger bucket = y

Kim sold 3 small buckets and 14 large buckets of popcorn for a total of $206.

3x + 14y = 206... Equation 1

Melody sold 11 small buckets and 11 large buckets of popcorn for a total of $231.

11x + 11y = 231.... Equation 2

What is the cost for a small bucket and a large bucket of popcorn?

3x + 14y = 206... Equation 1

11x + 11y = 231 ....... Equation 2

We solve using Elimination method

Multiply Equation 1 by 11 and Equation 2 by 3 to Eliminate x

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We subtract Equation 4 from Equation 3

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x = $8

Hence, the cost of

A small bucket = x = $8

A Larger bucket = y = $13

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3 years ago
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vesna_86 [32]
Same would need to get at least a 95% on the next test, if he would like to receive a total average of an 80%
4 0
3 years ago
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DIA [1.3K]

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6 0
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