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Nitella [24]
3 years ago
12

Find the distance between the two points rounding to the nearest tenth (if necessary).

Mathematics
1 answer:
vovangra [49]3 years ago
7 0

Answer: 10.3

Step-by-step explanation:

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On the map of a town, 1 cm represents 6 miles. Find the distance represented by 4.5 cm
Daniel [21]

Answer:

27 miles

Step-by-step explanation:

1cm is 6 miles,

4.5cm is ?miles

?=6*4.5/1=27

6 0
3 years ago
Help I be trying so but can figure out the answer
Sphinxa [80]

Answer:

b

Step-by-step explanation:

Surface of the earth =3959×3.14

=12,437.565

if 20%is suitable so we multiply it by the surface

12,437.565×0.2=2,487.513 per people

2,487.513/7,700,00,00

So I think it will be the closest to b

4 0
3 years ago
Read 2 more answers
Practice
TEA [102]

Answer:

B. -0.5

Step-by-step explanation:

I calculated it logically

4 0
3 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
Solve x:<br><br> 3x + 99x= 1224<br><br> 10 pts
Masja [62]
Answer is 12
Reason
Combine like terms
3x + 99 x = 1224
102x = 1224
Now solve for x
Divide both sides by 102
x= 12
3 0
1 year ago
Read 2 more answers
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