I think the answer can be grams but I might be wrong hope u get the answer right good luck hope you get it or can be it's grams per mole
The 2 L of sucrose stock solution would contain similar
concentration with the 100 mL aliquot. Therefore the concentration of aliquot
is still 2 M.
The molar mass of sucrose is 342.3 g / mol. Therefore the
mass in a 100 mL (0.1 L) aliquot is:
mass = (2 mol / L) * 0.1 L * (342.3 g / mol)
<span>mass = 68.46 g</span>
It depends on the weight and the high and the location of the object. I hop I helped. Have a great day