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nevsk [136]
3 years ago
14

the pressure of a has is 1.0 atm and it occupies a volume of 2.50 L. What will he the new volume of this has if the pressure is

increased to 2.0 atm
Chemistry
1 answer:
NikAS [45]3 years ago
6 0

Answer:

<h2>1.25 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{1 \times 2.5}{2}  =  \frac{2.5}{2}  \\

We have the final answer as

<h3>1.25 L</h3>

Hope this helps you

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olga2289 [7]
Balancing the equation, we get:

2C₂H₆O + O₂ → 2C₂H₄O₂ + 2H₂O

So 
α = 2
β = 1
γ = 2
δ = 2
4 0
2 years ago
Which subatomic particles are located in MOST of the space within an atom? A. protons B. neutrons C. electrons
IRISSAK [1]

Answer: -

C. Electrons

Explanation: -

Most of the space in an atom is empty. Through this space the electrons revolve around the centrally placed nucleus.

Inside the nucleus are present the protons and the neutrons. The nucleus size is very small compared to the rest of the atom.

Electrons carry negative charge, protons are positive and neutrons are neutral.

7 0
2 years ago
In every balanced chemical equation, each side of the equation has the same number of ____. select all that are true.
rjkz [21]
Hey..

It's answer should be atoms...
6 0
3 years ago
Scientist can use the of minerals to tell them apart A.sound B.length C.size D.color
ipn [44]

Answer:

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Explanation:

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7 0
3 years ago
Can somebody help me, please!
zavuch27 [327]

Answer:

Rubidium-85=61.2

Rubidium-87=24.36

Atomic Mass=85.56 amu

Explanation:

To find the atomic mass, we must multiply the masses of the isotope by the percent abundance, then add.

<u>Rubidium-85 </u>

This isotope has an abundance of 72%.

Convert 72% to a decimal. Divide by 100 or move the decimal two places to the left.

  • 72/100= 0.72      or        72.0 --> 7.2 ---> 0.72

Multiply the mass of the isotope, which is 85, by the abundance as a decimal.

  • mass * decimal abundance= 85* 0.72= 61.2

Rubidium-85=61.2

<u>Rubidium-87</u>

This isotope has an abundance of 28%.

Convert 28% to a decimal. Divide by 100 or move the decimal two places to the left.

  • 28/100= 0.28       or        28.0 --> 2.8 ---> 0.28

Multiply the mass of the isotope, which is 87, by the abundance as a decimal.

  • mass * decimal abundance= 87* 0.28= 24.36

Rubidium-87=24.36

<u>Atomic Mass of Rubidium:</u>

Add the two numbers together.

  • Rb-85 (61.2) and Rb-87 (24.36)
  • 61.2+24.36=85.56 amu
4 0
3 years ago
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