Answer:
The unknown element is Carbon.
(a) X is Carbon, its oxide is of acidic nature
(b) C+ O2 → CO2
Explanation:
We are given an unknown element that reacts with oxygen.
X + O2 → XO2
It is given that the oxide XO2 turns blue litmus red which is shown by acids, so XO2 is an acidic oxide. Also X will be a Non metal because Non metallic oxide is Acidic in nature.
The Oxide XO2 is dissolving is water. The oxide upon reacting with water will give an Acid.
XO2 type of oxide is found in the 14th group of the periodic table generally
So we have options like C, Si and Ge as these only have the Acidic oxide.
But when it comes to reactivity with water Only Carbon satisfies the need so the unknown element X is C.
CO2 + H2O → H2CO3 which is an acid.
(a) Element X is Carbon (C), The nature of the compound formed is Acidic.
(b) The reaction given will be as follows
C+ O2 → CO2
Therefore the unknown element is Carbon.
Most fertilizers are rich in nitrogen and phosphorous because they have to replenish nitrogen and phosphorous in the soil, which are essential for plant growth. If they didn't have this, the soil would have to wait fro another cycle and this would hinder plant growth. The correct answer is C.
Answer:
Chemical
Explanation:
A chemical change is formed because the state of the substances can't be changed to its previous state. Therefore it's a chemical change only.
Answer:
The answers to the question are
(a) The the mg/L of H₃PO₄is 1462.05 g
(b) The molarity of H₃PO₄ in the solution is 14.92 mol/L
(c) The normality of H₃PO₄ in the solution 44.85 eq/L
Explanation:
(a) The commercially available H₃PO₄ has a concentration of 85.5 percent by weight, therefore
The mass of H₃PO₄ is found by
Density of water = 1.71 g/ml
mass of one liter of acid solution = 1.71 ×1000 = 1710 g
Therefore 85.5 % by weight of H₃PO₄ =1710×85.5/100 = 1462.05 g
Therefore we have 1462.05 g/L of H₃PO₄
Molar mass of H₃PO₄ = 97.994 g/mol
(b)Therefore the number of moles in 1462.05 g = 14.92 moles and the molarity = 14.92 mol/L
(c) The Normality = = 1465.05÷(1×97.994/3) = 44.85 eq/L