Question

Write empirical formula

Answer 1

Answer:

$ZnCl_{2}\\ZnO\\\\FeCl_{2}\\FeO$

Explanation:

$Zn^{2+}Cl^{-}_{2}--->ZnCl_{2}\\Zn^{2+}O^{2-}--->ZnO\\\\Fe^{2+}Cl^{-}_{2}---->FeCl_{2}\\Fe^{2+}O^{2-}--->FeO$