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3 years ago

Converting decimals into fractions

Mathematics

2 answers:

ira [324]3 years ago

8 0

You can put a decimal as a percent he convert to a fraction or something

Maurinko [17]3 years ago

6 0

Example:
Step 1- write down .75 or your own number divided by 1
0.75/1= .75

Step 2- turn it into a whole number and the numerator has to be 100 (like a percentage)
75/100

Step 3- simplify the fraction as many times as possible
75/100 divided by 5= 15/20
Then divide that again to its simplest number 15/20 divided by 5 gets you 3/4

You might be interested in

Solve this system of equations by elimination: 8x+9y=48 12x+5y=21

Olin [163]

Answer:

Let's solve your system of equations by elimination.

8x+9y=48;12x+5y=21

Steps:

Multiply the first equation by 5,and multiply the second equation by -9.

5(8x+9y=48)

−9(12x+5y=21)

Becomes:

40x+45y=240

−108x−45y=−189

Add these equations to eliminate y:

−68x=51

Then solve−68x=51for x:

−68x /−68 = 51 /−68 (Divide both sides by -68)

x= −3 /4

Now that we've found x let's plug it back in to solve for y.

Write down an original equation:

8x+9y=48

Substitute

−3 /4

8x+9y=48:

8( −3 /4 )+9y=48

9y−6=48 (Simplify both sides of the equation)

9y−6+6=48+6 (Add 6 to both sides)

9y=54

9y /9 = 54 /9 (Divide both sides by 9) y=6

Answer: x= −3 /4 and y=6

Hope This Helps! Have A Nice Day!!

7 0

3 years ago

I need help with this :/

hoa [83]

Answer:

Plz mark me brainliest!!!!

Step-by-step explanation:

180

270

380

6 0

3 years ago

Which choice is the solution for this system ? 2x − 5y = 14 x + 3 2 y = 5

VashaNatasha [74]

Answer:

The required solution is (5.75,-0.5). It can be written as $(\frac{11}{4},-\frac{1}{2})$ .

Step-by-step explanation:

The given equations are

$2x-5y=14$ .... (1)

$x+\frac{3}{2}y=5$ .... (2)

Multiply the equation (2) by 2.

$2x+3y=10$ .... (3)

Subtract equation (1) from equation (3).

$2x+3y-(2x-5y)=10-14$

$2x+3y-2x+5y=-4$

$8y=-4$

$y=-\frac{1}{2}=-0.5$

Put this value in equation (1).

$2x-5(-0.5)=14$

$2x+2.5=14$

$2x=11.5$

$x=5.75$

Therefore the required solution is (5.75,-0.5). It can be written as $(\frac{11}{4},-\frac{1}{2})$ .

3 0

3 years ago

A product can be made in sizes huge, average and tiny which yield a net unit profit of $14, $10, and$5, respectively. Three cent

navik [9.2K]

Answer:

The model is:

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃ to maximize

Subject to:

First center X₁₁ + X₂₁ + X₃₁ ≤ 550

Second center X₁₂ + X₂₂ + X₃₂ ≤ 750

Third center X₁₃ + X₂₃ + X₃₃ ≤ 275

22* X₁₁ + 16* X₂₁ + 9*X₃₁ ≤ 11000

22* X₁₂ + 16* X₂₂ + 9*X₃₂ ≤ 2700

22*X₁₃ + 16* X₂₃ + 9*X₃₃ ≤ 3400

X₁₁ + X₁₂ + X₁₃ ≤ 710

X₂₁ + X₂₂ + X₂₃ ≤ 900

X₃₁ + X₃₂ + X₃₃ ≤ 350

2700*(X₁₁ + X ₂₁ + X₃₁) - 11000*(X₁₂ + X₂₂ + X₃₂) = 0

3400*(X₁₁ + X ₂₁ + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

Xij >= 0

Step-by-step explanation:

Let´s call Xij product size i produced in center j

According to this, we get the following set of variable

X₁₁ product size huge produced in center 1

X₁₂ product size huge produced in center 2

X₁₃ product size huge produced in center 3

X₂₁ product size average produced in center 1

X₂₂ product size average produced in center 2

X₂₃ product size average produced in center 3

X₃₁ product size-tiny produced in center 1

X₃₂ product size-tiny produced in center 2

X₃₃ product size-tiny produced in center 3

Then Objective function is

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃

Constrains

Center capacity

1.- First center X₁₁ + X₂₁ + X₃₁ ≤ 550

2.- Second center X₁₂ + X₂₂ + X₃₂ ≤ 750

3.- Third center X₁₃ + X₂₃ + X₃₃ ≤ 275

Water available

1.- 22* X₁₁ + 16* X₂₁ + 9*X₃₁ ≤ 11000

2.- 22* X₁₂ + 16* X₂₂ + 9*X₃₂ ≤ 2700

3.- 22*X₁₃ + 16* X₂₃ + 9*X₃₃ ≤ 3400

Demand constrain

Product huge

X₁₁ + X₁₂ + X₁₃ ≤ 710

Product average

X₂₁ + X₂₂ + X₂₃ ≤ 900

Product tiny

X₃₁ + X₃₂ + X₃₃ ≤ 350

Fraction SP/CC must be the same

First and second centers fraction SP/CC

(X₁₁ + X ₂₁ + X₃₁)/ 11000 = (X₁₂ + X₂₂ + X₃₂)/ 2700

2700*(X₁₁ + X ₂₁ + X₃₁) - 11000*(X₁₂ + X₂₂ + X₃₂) = 0

First and third centers fraction SP/CC

(X₁₁ + X ₂₁ + X₃₁)/ 11000 = ( X₁₃ + X₂₃ + X₃₃)/ 3400

3400*(X₁₁ + X ₂₁ + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

The model is:

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃

Subject to:

First center X₁₁ + X₂₁ + X₃₁ ≤ 550

Second center X₁₂ + X₂₂ + X₃₂ ≤ 750

Third center X₁₃ + X₂₃ + X₃₃ ≤ 275

22* X₁₁ + 16* X₂₁ + 9*X₃₁ ≤ 11000

22* X₁₂ + 16* X₂₂ + 9*X₃₂ ≤ 2700

22*X₁₃ + 16* X₂₃ + 9*X₃₃ ≤ 3400

X₁₁ + X₁₂ + X₁₃ ≤ 710

X₂₁ + X₂₂ + X₂₃ ≤ 900

X₃₁ + X₃₂ + X₃₃ ≤ 350

2700*(X₁₁ + X ₂₁ + X₃₁) - 11000*(X₁₂ + X₂₂ + X₃₂) = 0

3400*(X₁₁ + X ₂₁ + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

Xij >= 0

6 0

3 years ago

Solve for x and y. 7x-4 # 4y+8 24# + 31

Darina [25.2K]

Answer:

7x-4 = -28

4y+8 = 4(y + 2)

Step-by-step explanation:

3 0

2 years ago