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amid [387]
2 years ago
13

A local charity is selling seats to a baseball game. Seats cost $16 each, and snacks cost an additional $4 each. The charity nee

ds to raise $296 to consider this event a success.
Enter a linear equation that describes the problem.

An equation for the amount of money raised for charity is = $296, where s is the number of seats sold, and y is the number of snacks sold.
Mathematics
2 answers:
Kruka [31]2 years ago
3 0

Answer:

$16s + $4y = 296

Step-by-step explanation:

Tamiku [17]2 years ago
3 0

Answer:

16x + 4y = 296

Step-by-step explanation:

X = Seats

Y = Snacks

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Profit, P(x), is the difference between revenue, R(x), and cost, C(x), so P(x) = R(x) - C(x). Which expression represents P(x),
harkovskaia [24]

Answer:

x^4-3x^3+x^2-4

Step-by-step explanation:

Given the following functions

R(x) = 2x^4 – 3x^3 + 2x – 1 and

C(x) = x^4 – x^2 + 2x + 3

We are to find the profit function P(x)

P(x) = R(x) - C(x)

P(x) = 2x^4 – 3x^3 + 2x – 1 - ( x^4 – x^2 + 2x + 3)

P(x) = 2x^4 – 3x^3 + 2x – 1 - x^4 + x^2 - 2x - 3

Collect the like terms

P(x) = 2x^4-x^4-3x^3+x^2+2x-2x-1-3

P(x) = x^4-3x^3+x^2+0-4

P(x) = x^4-3x^3+x^2-4

Hence the required profit function P(x) is x^4-3x^3+x^2-4

5 0
3 years ago
Read 2 more answers
Simplify:<br> The square root of p squared
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Answer:

p

Step-by-step explanation:

\sqrt{p^2} = p

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2 years ago
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Answer:

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8 0
3 years ago
Travis jogged to his friend's house 10 miles away and then got a ride back home. It took him 2 hours longer to jog there than ri
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Using the relation between velocity, distance and time, it is found that his jogging rate was of 4.5 mph.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is <u>distance divided by time,</u> hence:

v = \frac{d}{t}

Jogging, his velocity was of v, while the time was of t + 2, for a distance of 10 miles, hence:

v = \frac{10}{t + 2}

Riding, his velocity was of 16, while the time was of t, also for a distance of 10 miles, hence:

v + 16 = \frac{10}{t}

Then, considering the first equation and replacing in the second:

\frac{10}{t + 2} + 16 = \frac{10}{t}

\frac{10}{t} - \frac{10}{t + 2} = 16

\frac{10t + 20 - 10t}{t(t + 2)} = 16

16t² + 32t - 20 = 0 -> t = 0.5.

Then his jogging rate in mph was:

v = \frac{10}{0.5 + 2} = 4.5

More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569

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8 0
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3 years ago
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