There’s an app that can solve this easily called photo math it’s what I used But x= 3
Answer:
x = 2 and y = 1.
Step-by-step explanation:
If in the given quadrilateral all angles ∠A, ∠B, ∠C, ∠D are 90°and opposite sides are equal, then this property of a quadrilateral concludes that the given quadrilateral is a rectangle.
5x - 4 = 2y + 4
5x - 2y = 4+4 =8--------(1)
and 5y + 1 = 3x
3x - 5y = 1--------(2)
We multiply equation 1 by 3 and equation 2 by 5
15x - 6y = 24------(3)
15x - 25y = 5------(4)
Now we subtract equation 4 from 3
15x - 6y - (15x - 25 y) = 24-5
15x -6y -15x + 25y =19
19y = 19
y = 1
By putting y = 1 in equation 1.
5x - 2 = 8
5x = 10
x = 2
Answer:
0.86
Step-by-step explanation:
Draw the triangle.
Since ∠J=90°, this is a right triangle, so we can use SOH-CAH-TOA to find sin∠I.
sin∠I = 56/65
sin∠I = 0.86

a ) The domain:
x^4 - 16 x² ≥ 0
x² ( x² - 16 ) ≥ 0
x² - 16 ≥ 0
x² ≥ 16
x ∈ ( - ∞, - 4 ] ∪ [ 4 , + ∞ )b ) f ` ( x ) =

=
( 2 x³ - 16 x ) / √(x^4 - 16 x²)c ) The slope of the tangent line at x = 5:
f ` ( 5 ) = ( 2 * 125 - 16 * 5 ) / √ ( 625 - 400 ) = 170 / 15 = 34 / 3
The slope of the line normal to the graph at x = 5:
m = - 3 / 34