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inessss [21]
3 years ago
11

Write an equation for a line with a slope of 5 and y-inter of -3

Mathematics
1 answer:
Daniel [21]3 years ago
6 0

Answer:

y=5x-3

Step-by-step explanation:

y=mx+b where m=slope and b= y-intercept

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Read 2 more answers
Okay now using distributive property write 2(4x-9) without parenthesis
riadik2000 [5.3K]
2(4x - 9) = 
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~Kiwi


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2 years ago
State if polygons are similar
Oksana_A [137]

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2 years ago
the vertex of this parabola is at (5,5). when the x-value is 6, the y-value is -1. what is the coefficient of the squared in the
zlopas [31]

Answer: OPTION D.

Step-by-step explanation:

The vertex form of a quadratic function is:

y= a(x - h)^2 + k

Where (h, k) is the vertex of the parabola and "a" is the coefficient of the squared in the parabola's equation.

We know that the vertex of this parabola is at (5,5) and we also know that when the x-value is 6, the y-value is -1.

Then  we can substitute values into  f (x) = a(x - h)^2 + k and solve for "a". This is:

-1= a(6- 5)^2 + 5\\\\-1=a+5\\\\-1-5=a\\\\a=-6

7 0
3 years ago
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