Answer:
79853709 with the exponent of 94
Step-by-step explanation:
Answer:
A. 605 mL of the 35% solution
B. 55 mL of the 95% solution
Step-by-step explanation:
It is given that, you need 660 mL of a 40% alcohol solution. On hand, you have 35% alcohol mixture. You also have a 95% alcohol mixture.
Let x and y be the amount of 35% alcohol solution and 95% alcohol solution (in mL) respectively.
So,
Amount equation:
...(1)
Alcohol equation :
...(2)
On solving (1) and (2), we get
Now, substitute y=55 in (1).
Therefore, we need 605 mL of the 35% solution and 55 mL of the 95% solution.
Answer:
Thank you so much made my day!
Step-by-step explanation:
Answer: 
Step-by-step explanation:
Given
The temperature of the liquid is
placed in an oven with temperature of
.
Initially difference in temperature of the two

According to the question
![\Rightarrow \dfrac{dT(t)}{dt}=77\cdot \Delta T\\\\\Rightarrow \dfrac{dT(t)}{dt}=77\times (450-T)\quad [\text{T=75}^{\circ}F\ \text{at t=0}]](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7BdT%28t%29%7D%7Bdt%7D%3D77%5Ccdot%20%5CDelta%20T%5C%5C%5C%5C%5CRightarrow%20%5Cdfrac%7BdT%28t%29%7D%7Bdt%7D%3D77%5Ctimes%20%28450-T%29%5Cquad%20%5B%5Ctext%7BT%3D75%7D%5E%7B%5Ccirc%7DF%5C%20%5Ctext%7Bat%20t%3D0%7D%5D)