Question

What are the coordinates of the center of a circle whose equation is (x + 10)2 + (y – 8)2 = 17?

Answer 1

we just need make inside square 0

x+10=0

x=-10

y-8=0

y=8

so the center is (-10,8)

Answer 2

Answer:

the center of the circle is (-10,8)

Third option is correct.

Step-by-step explanation:

The equation of the circle is $(x+10)^2+(y-8)^2=17$

This equation can be rewritten as

$(x-(-10))^2+(y-8)^2=17$

The standard form of the circle is given by

$(x-h)^2+(y-k)^2=r^2$, where (h,k) is the center of the circle.

On comparing the given equation of circle with the standard form

h = -10, k = 8

Hence, the center of the circle is (-10,8)

Third option is correct.