Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
Percent of decrease :
Original - New / Original
so...
80 - 52 / 80 ---->
28/80
.35 multiply by 100 to get percent
35% increase Hope I helped if you have any questions let me know! :)
Answer:
b
Step-by-step explanation:
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I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform

and

, then

Given that

and

So you have

From Table of Laplace Transform, you have

and hence

So you have

.
Hope this helps...