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Greeley [361]
3 years ago
5

Please help!! Will give brainliest if correct!!

Mathematics
1 answer:
Natalija [7]3 years ago
7 0

Answer:

12 is your answer........

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Through any _____ non-collinear points there is exactly one plane
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I believe it is 3 non-collinear points.

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$1.12 for 8.2 ounces help as soon as possible
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I need it's answer please help me
Luda [366]
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Example 2
Arada [10]

Answer:

y=x-2

Step-by-step explanation:

If you have drawn the graph of y = x^2 - 3x + 1.

To determine the equation of the line which  should be drawn to solve the equation:  x² - 4x +3=0

Simply carry out the subtraction: x^2 - 3x + 1 -(x^2 - 4x +3)

\implies x^2 -3x + 1-x^2 + 4x -3 \\= x^2 - x^2+ 4x - 3x-3  + 1\\=x-2

The equation of the line which should be drawn is: y=x-2

What this means is simply:

If

y = x^2 - 3x + 1$ and $y=x-2,$ then:\\x^2 - 3x + 1=x-2\\x^2 - 3x + 1-x+2=0\\x^2 - 4x + 3=0

5 0
3 years ago
(x⁴ + 3x³ – 2x² + 5) + (2x⁴ – 5x³ + 4x – 15).
olya-2409 [2.1K]

Answer:

\left(x^4+3x^3-2x^2+5\right)+\left(2x^4-5x^3+4x-15\right)

= x^4+3x^3-2x^2+5+2x^4-5x^3+4x-15

=x^4+2x^4+3x^3-5x^3-2x^2+4x+5-15

=x^4+2x^4-2x^3-2x^2+4x+5-15

=3x^4-2x^3-2x^2+4x+5-15

=3x^4-2x^3-2x^2+4x-10

OAmalOHopeO

8 0
3 years ago
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