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3 years ago

I didn’t pay attention to class cause I had to make my sister lunch today can someone explain what that is ? I’ll give brainlest

Mathematics

2 answers:

Black_prince [1.1K]3 years ago

7 0

Answer:

Not a function.

Step-by-step explanation:

Its not a function because there are two outputs (i.e. when you draw a vertical line in the diagram, you cross over the curve to times)

A function has ONLY ONE INPUT AND OUTPUT.

ASHA 777 [7]3 years ago

4 0

Answer:

Definitely not a function.

Step-by-step explanation:

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antoniya [11.8K]

Answer:

The correct answer is 5 11/12

Step-by-step explanation:

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3 years ago

Covert 6 2/3 to a fraction

Free_Kalibri [48]

It’s already a fraction so it cannot be simplified anymore

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4 years ago

Find x round. your answer to the nearest tenth of a degree

Juli2301 [7.4K]

Answer:

x = 55.6

Step-by-step explanation:

Recall the 3 main trig functions

Sin = opposite / hypotenuse

Cos = adjacent / hypotenuse

Tan = opposite / adjacent

Note that hypotenuse = longest side length

We want to find angle "x".

We are given its opposite side length ( 19 ) as well as the adjacent side length

When dealing with the opposite and adjacent we use tan

Tan = Opp / Adj

Opp = 19 and Adj = 13

Tan(x) = 19/13

* take the inverse tan of both sides *

x = 55.6

7 0

3 years ago

Maya had some marbles. Jada took 5 marbles away from Maya. Now Maya has 8 marbles left. How many marbles did Maya have at the be

Nastasia [14]

<h2>Maya had 13 marbles at the beginning</h2>

4 0

3 years ago

Read 2 more answers

Help plsss

LenKa [72]

<h3></h3><h2>⭐ Development:</h2><h3></h3>

Having the expression, let's modify it so it becomes a 2nd degree equation:

$\large {\text {$ \sf \cfrac{1}{2x^2} -2 = 0 $}}$

Now, we will multiply per 2x² both sides of equation...

$\large {\text {$ \sf \cfrac{1}{2x^2}\cdot \:2x^2-2\cdot \:2x^2=0\cdot \:2x^2 $}$

$\searrow$

$\large {\text {$ \sf 1-4x^2=0$}}$

We have to write in standard form...

$\large {\text {$ \sf -4x^2+1 = 0 $}}$

<u />

$\large {\text{$\sf x=\cfrac{-b\pm\sqrt{b^2-4ac}}{2a} \quad\rightarrow\quad x=\cfrac{-0\pm\sqrt{0^2-4\cdot (-4) \cdot1} }{2\cdot (-4) } \:\rightarrow\:\: x=\cfrac{-0^2 \pm4}{2 \cdot(-4)} $}}$

$\huge {\text {$ \sf \downarrow$}}$

$\large {\text {$\sf {\bf x_1} = \cfrac{-0+4}{2\left(-4\right)}= \cfrac{-1}{2} $}}$ $\large {\text {$\sf {\bf x_2 }=\cfrac{-0-4}{2\left(-4\right)} = \cfrac{1}{2} $}}$

At this point, we're going to add the values of x₁ and x₂:

$\large {\boxed {\boxed { \bf x_1 + x_2= -\cfrac{1}{2}+ \cfrac{1}{2} = 0} }}$

$\huge {\text {$ \it Alternative \: A $}}$

8 0

3 years ago