Answer:
50/96
Step-by-step explanation:
I assume the table is:
![\left[\begin{array}{cc}Result&Total\\1&15\\2&13\\3&16\\4&17\\5&15\\6&20\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7DResult%26Total%5C%5C1%2615%5C%5C2%2613%5C%5C3%2616%5C%5C4%2617%5C%5C5%2615%5C%5C6%2620%5Cend%7Barray%7D%5Cright%5D)
Even numbers are 2, 4, and 6. The total number of times she rolled an even number is 13 + 17 + 20 = 50.
So the probability is 50/96.
Take the root of both sides, and then solve.
c = sqrt a^2 + b^2, - sqrt a^2 + b^2.
K + a + h = 50
a = 2h
k = h - 10
(h - 10) + 2h + h = 50
4h - 10 = 50
4h = 50 + 10
4h = 60
h = 60/4
h = 15 <=== Henry sent 15
a = 2h
a = 2(15)
a = 30 <=== Aldo sent 30
k = h - 10
k = 15 - 10
k = 5 <=== Keiko sent 5
Answer:
131°
Step-by-step explanation:
Since KNJ is a straight line,
∡KNM +∡MNJ= 180° (adj. ∡s on a str. line)
(8x -5)° +(4x -19)°= 180°
<em>Simplify:</em>
12x -24= 180
<em>+</em><em>2</em><em>4</em><em> </em><em>on </em><em>both </em><em>sides</em><em>:</em>
12x= 180 +24
12x= 204
<em>Divide</em><em> </em><em>both </em><em>sides </em><em>by </em><em>1</em><em>2</em><em>:</em>
x= 204 ÷12
x= 17
∡KNM
= (8x -5)°
= [8(17) -5]°
= (136 -5)°
= 131°
