Answer is 
Choice C
I used the power rule for integrals.
 
        
        
        
To find the percentage,here's what we can do:

The percentage would then be:
=63/420×100%
=3/20×100%
=0.15×100%
=15%
Therefore the answer is 15%.
Hope it helps!
 
        
        
        
Answer:
The range of T is a subspace of W.
Step-by-step explanation:
we have T:V→W
This is a linear transformation from V to W
we are required to prove that the range of T is a subspace of W
0 is a vector in range , u and v are two vectors in range T
T = T(V) = {T(v)║v∈V}
{w∈W≡v∈V such that T(w) = V}
T(0) = T(0ⁿ)
0 is  Zero in V
0ⁿ  is zero vector in W
T(V) is not an empty subset of W
w₁, w₂   ∈ T(v)
(v₁, v₂ ∈V)
from here we have that
T(v₁) = w₁
T(v₂) = w₂
t(v₁) + t(v₂) = w₁+w₂
v₁,v₂∈V
v₁+v₂∈V
 with a scalar ∝
T(∝v) = ∝T(v)
such that 
T(∝v) ∈T(v)
so we have that T(v) is a subspace of W. The range of T is a subspace of W.