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4 years ago

Write the expression as a single natural logarithm. 3ln3 + 3lnc

1 answer:

5 0

Using the rules of logarithms, you can change it to

ln( $3^{3}$ ) + ln( $c^{3}$ ) =

ln(27 $c^{3}$ )

This is because when you have a factor in front of a logarithm, that turns into an exponent, and when you add logarithms, you multiply the factors inside of the logarithm.

So your final answer is D.

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Is 48.4 closest to 49 on a number line

liubo4ka [24]

Answer:

if there are any less than 4.84 then yes it is.

Step-by-step explanation:

please give brainliest and hope this helps

3 0

4 years ago

A youth chorus has 30 members. There are 14 boys in the chorus.

zalisa [80]

<span>D. 7/8

Hope it helped :)</span>

6 0

3 years ago

What is the value of E(-1) n (3n+2)?

RoseWind [281]

<h3>Answer: C) 6</h3>

====================================================

Explanation:

The weird looking E symbol is the greek uppercase letter sigma. It refers to a sum.

It tells us to add up terms in the form (-1)^n*(3n+2) where n is an integer ranging from n = 1 to n = 4.

------------------

If n = 1, then we have

(-1)^n*(3n+2) = (-1)^1*(3*1+2) = -5

Let A = -5 as we'll use it later.

------------------

If n = 2, then

(-1)^n*(3n+2) = (-1)^2*(3*2+2) = 8

Let B = 8 since we'll use this later as well

------------------

If n = 3, then

(-1)^n*(3n+2) = (-1)^3*(3*3+2) = -11

Let C = -11

-------------------

If n = 4, then

(-1)^n*(3n+2) = (-1)^4*(3*4+2) = 14

Let D = 14.

--------------------

We'll add up the values of A,B,C,D to get the final answer

A+B+C+D = -5+8+(-11)+14 = 6

This means that

$\displaystyle \sum_{n=1}^{4}(-1)^n(3n+2) = 6$

6 0

3 years ago

Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 a

krok68 [10]

Answer:

Jessie scored higher than Reagan.

Step-by-step explanation:

We are given that Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 and standard deviation 100.

Jessie scored 30 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 17 and standard deviation 5.

For finding who performed better on the standardized exams, we have to calculate the z-scores for both people.

1. <u>Finding z-score for Reagan;</u>

Let X = distribution of SAT scores

SO, X ~ Normal( $\mu=1000, \sigma^{2}=100^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 1000

$\sigma$ = standard deviation = 100

Now, Reagan scored 1140 on the SAT, that is;

z-score = $\frac{1140-1000}{100}$ = 1.4

2. <u>Finding z-score for Jessie;</u>

Let X = distribution of ACT scores

SO, X ~ Normal( $\mu=17, \sigma^{2}=5^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 17

$\sigma$ = standard deviation = 5

Now, Jessie scored 30 on the ACT, that is;

z-score = $\frac{30-17}{5}$ = 2.6

This means that Jessie scored higher than Reagan because Jessie's standardized score was 2.6, which is 2.6 standard deviations above the mean and Reagan's standardized score was 1.4, which is 1.4 standard deviations above the mean.

6 0

3 years ago

Brainliest if you give steps

Tems11 [23]

Answer:

Step-by-step explanation:

try 65 if not then 55

8 0

3 years ago