Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
(2h – 3)(3h + 4) is the same thing as
2h(3h + 4) - 3(3h + 4)
6h^2 + 8h - 9h - 12
6h^2 - h - 12
Answer B.
14720 is answer. or product
Answer:
-2
Step-by-step explanation:
x-8=-10
x=-10+8
x=-2
